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jek_recluse [69]
3 years ago
10

Is y-x=2x-2/3y a linear or nonlinear m?

Mathematics
1 answer:
Ivanshal [37]3 years ago
6 0

Answer:

linear

Step-by-step explanation:

y - x = 2x - \frac{2y}{3}

\frac{5y}{3} = 3x

y = 9x/5

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Well, you would have to mutiply the length and width and then divide that by 2 to get your area for the triangle
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Consider the functions f(x) = 2x - 3 and g(x) = 6 + 8/x. Solve for f(g(4))
ExtremeBDS [4]

Answer:

13

Step-by-step explanation:

Given the equations f(x) = 2x - 3 and g(x) = 6 + 8/x.

We want to find f(g(4))

Essentially, what we are doing, is plugging in 4 into x for g(x) and the outcome of that is what we plug into x for f(x)

So first lets plug in 4 into x for g(x)

g(x) = 6 + 8/x.

We want to find g(4)

g(4) = 6 + 8/4

First divide 8 by 4

g(4) = 6 + 2

Then add 6 and 2

g(4) = 8

Now that we have found g(4) we want to plug the value of g(4), so 8 into f(x)

f(x) = 2x - 3

we want to find f(8)

f(8) = 2(8) - 3

* multiply 2 and 8 *

f(8) = 16 - 3

* subtract 3 from 16 *

f(8) = 13

and we are done!

So we can conclude that f(g(4)) = 13

5 0
3 years ago
Which is less, 3 or 30? Explain how you know
r-ruslan [8.4K]

Answer:

3

Step-by-step explanation:

3 is closer to 0

7 0
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Please help 10 points and brainliest picture attached
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Step-by-step explanation:

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3 years ago
A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and
natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: E=k\frac{q}{r^{2} }; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: p=\frac{q}{A}; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: S=4\pi r^{2}; which gives us the surface of a sphere.

The inner surface: Si=4\pi (0.06m)^{2} = 0.04 m^{2}

The outer surface: S=4\pi (0.08m)^{2}=0.08m^{2}

Now we can calculate the charges,

Inner charge: Qi=pA=(-100\frac{nC}{m^{2} } )(0.04m^{2} )=-4nC

Outer charge: Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC

Then, we are able to calculate both fields:

Inner field: Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}

Outer field:  Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

3 0
3 years ago
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