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algol13
4 years ago
15

What’s is the answer to 4(6)

Mathematics
2 answers:
Nuetrik [128]4 years ago
4 0

Answer: 24

Step-by-step explanation:

4 time 6 = 24

ehidna [41]4 years ago
3 0

Answer:24

Step-by-step explanation: put into a calulater 4 times 6 then u have your answer.

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The dot plot shows the number of hours, to the nearest
Hoochie [10]

Answer: Fifth grade mean: 4.67

Seventh grade mean: 3.46

Fifth grade median: 5

Seventh grade median: 3.5

Step-by-step explanation: I just did the question

3 0
3 years ago
Given the equation 5x − 4 = –2(3x + 2), solve for the variable. Explain each step and justify your process.
blagie [28]
A.
5x-4=-2(3x+2) \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
5x-4=-2 \times 3x-2 \times 2 \\
5x-4=-6x-4 \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 6x to both sides} \\
11x-4=-4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 4 to both sides} \\
11x=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{divide both sides by 11} \\
x=0

B.
3(2x-4)=5x-1 \\
6x-12=5x-1 \\
\boxed{11x-12=-1} \Leftarrow \hbox{the first mistake} \\
11x=11 \\
\boxed{x=11} \Leftarrow \hbox{the second mistake}

Megan's solution isn't correct.
The first mistake: she subtracted 5x from the right-hand side of the equation, but added 5x to the left-hand side.
The second mistake: she divided the right-hand side of the equation by 11, but didn't divide the left-hand side.

The correct solution:
3(2x-4)=5x-1 \ \ \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
3 \times 2x+3 \times (-4)=5x-1 \\ 6x-12=5x-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{subtract 5x from both sides} \\
x-12=-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  |\hbox{add 12 to both sides} \\
x=11
3 0
3 years ago
The Kings Dominion Gold Pass costs $89. If you buy it the first week of
Eddi Din [679]

Answer:

$75.65

Step-by-step explanation:

1 - .15 = .85 = 85% of the price is what you pay

89 • .85 = $75.65

7 0
3 years ago
For each sequence, find the first 4 terms and the 10th term.<br> A) n+5<br> B)2n-1
snow_tiger [21]

Answer:

see explanation

Step-by-step explanation:

(a)

To find the first 4 terms substitute n = 1, 2, 3, 4 into the n th term formula.

a₁ = 1 + 5 = 6

a₂ = 2 + 5 = 7

a₃ = 3 + 5 = 8

a₄ = 4 + 5 = 9

For the 10 th term substitute n = 10, that is

a₁₀ = 10 + 5 = 15

The first 4 terms are 6, 7, 8, 9 and the 10 th term is 15

(b)

Substitute n = 1, 2, 3, 4 and 10 into the n th term formula

a₁ = 2(1) - 1 = 2 - 1 = 1

a₂ = 2(2) - 1 = 4 - 1 = 3

a₃ = 2(3) - 1 = 6 - 1 = 5

a₄ = 2(4) - 1 = 8 - 1 = 7

a₁₀ = 2(10) - 1 = 20 - 1 = 19

The first 4 terms are 1, 3, 5, 7 and the 10 th term is 19

5 0
3 years ago
For what value of x is (2x^2+8x)/(x+4)(x^2-9) undefined?
irakobra [83]

Answer:

The value at x =3 is undefined for the given expression

Step-by-step explanation:

Given expression is \frac{2x^2+8x}{(x+4)(x^2-9)}

To find for what value of x is undefined in the given expression :

\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x(x+4)}{(x+4)(x^2-9)}

=\frac{2x}{x^2-9}

\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x}{x^2-9}

If we put x=3 in the above expression we get

\frac{2x}{x^2-9)}=\frac{2(3)}{3^2-9}

=\frac{6}{9-9}

=\frac{6}{0}

Therefore \frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{6}{0}

The value at x =3 is undefined for the given expression

7 0
3 years ago
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