They can NOT. A right angle is 90°. An obtuse angle is greater than 90°. All the angles in a triangle must add up to exactly 180°. If two angles are greater than 90° then they will add up to greater than 180, beacuse 90 plus 90 equals 180. You cannot have a triangle with two obtuse angles because they will add up to greater than 180°.
Solution:
1. Move all terms to one side
<span>25{x}^{2}+40x+16-28=0</span>
2. Simplify <span>25{x}^{2}+40x+16-28 to <span>25<span>x<span><span>2</span><span></span></span></span>+40x</span></span><span><span>−12</span></span>
<span>25{x}^{2}+40x-12=0</span>
3. Apply the Quadratic Formula<span>x=\frac{-40+20\sqrt{7}}{50},\frac{-40-20\sqrt{7}}{50}
</span>
4. Simplify solutions
<span>x=-\frac{2(2-\sqrt{7})}{5},-\frac{2(2+\sqrt{7})}{5}</span>
Done!
Answer:
10
Step-by-step explanation:
1. The area of triangle is = (A*h)/2, where h is the height grounded on side A.
2. Given the height 5 and the side 4 we get S(area)=(5*4)/2=10.
Y=2x-4
X=2
X+2y=10
X+2x0=10
X+0=10 therefore, x=10
Answer:
Step-by-step explanation:
First find the slope(m) between (0,-5) and (-5,-6)
m = 
= 
= 
= 
y = x -5
I attached the graph. I used desmos.
Hope that helps!
