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Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
Answer:
The correct answer is 6 cm.
Step-by-step explanation:
The measure of all angles of the triangle is given to be 60 degrees. This invariably means we are talking about an equilateral triangle as all angles of an equilateral triangle are equal.
Also all sides of an equilateral triangle is known to be equal. Therefore the measure of all sides of the concerned triangle are equal.
Given the measure of two length of sides are 6 cm respectively.
Therefore the length of side 3 is 6 cm, equal to the other two sides.
21/186
Answer: 7/62
Hope this helps!!!!!!!
0.0307 or what are you giving us here?
0.006
That's you're answer
