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2 years ago

I need help with this math problem for delta math and im not good at it

Mathematics

2 answers:

shutvik [7]2 years ago

6 0

Answer:

<h2>hope it helps.</h2><h2>stay safe healthy and happy.</h2>

kupik [55]2 years ago

4 0

i just did that but forgot to take a picture and some reason i can't but i basically got the same thing as the other person who answered.

Step-by-step explanation:

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PLEASE HELP ME I NEED IT QUICK I WILL GIVE BRAINLIEST

hodyreva [135]

Answer:

The slope of function A is 2 times the slope of function B.

Step-by-step explanation:

In function A, every-time the input goes up 1 the output will also go up one. In function B, every time the input goes up by 1, the output goes up by two. Therefore, the slope of function A is 1 but the slope of function B is 1/2.

1/2*2=1

7 0

3 years ago

Jung-Su's father gave him $144. Jung-Su bought 4 books, each of which cost $9. How much money does Jung-Su have left?

Ghella [55]

Answer:

$108

Step-by-step explanation:

9+9+9+9=36

144-36=108

lol

7 0

2 years ago

Read 2 more answers

What L is alternate interior at L6?<br><br> A. L3<br> B. L5 <br> C. L1<br> D. L4

nikdorinn [45]

Answer:

Step-by-step explanation:

3 0

2 years ago

The median and mean of these numbers:

aleksandr82 [10.1K]

Answer:

Mean : ≈ 12.7

Median: ≈ 13.5

Step-by-step explanation:

To find the mean you must add all the numbers and divide by the # of numbers in the set.

8+12+13+14+14+15 = 76

76/6 ≈ 12.7

To find the median you have to order the numbers from least to greatest, the middle number should be the median, but in this case two numbers are in the middle.

8, 12, 13, 14, 14, 15

So you have to add 14 and 13, which is 27.

Then divide by 2 which is ≈ 13.5

8 0

2 years ago

The percentage of body fat of a random sample of 36 men aged 20 to 29 found a sample mean of 14.42. Find a 95% confidence interv

Rina8888 [55]

Answer:

$14.42-1.96\frac{6.95}{\sqrt{36}}=12.150$

$14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690$

So on this case the 95% confidence interval would be given by (12.150;16.690)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=14.42$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=6.95$ represent the population standard deviation

n=36 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$

Now we have everything in order to replace into formula (1):

$14.42-1.96\frac{6.95}{\sqrt{36}}=12.150$

$14.42+ 1.96\frac{6.95}{\sqrt{36}}=16.690$

So on this case the 95% confidence interval would be given by (12.150;16.690)

5 0

3 years ago