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3 years ago

Below are two different functions, f(x) and g(x). What can be determined about their y-intercepts?

1 answer:

4 0

D-cannot be determined. g(x) is a vertical function, which is not a function. You cannot have the same x-value repeated. Because of this, g(x) has no y-intercept, and the relationship cannot be determined

You might be interested in

Can you add a whole number to a number with a variable

jeyben [28]

No, u cant. Because they are not like terms

Examples :
1 + 2v....cannot add or subtract because they are not like terms
2v + 4v = 6v...u can if they have exactly the same variable
3x^2 + 2x...cant
x^2 + 4x^2...can...= 5x^2
3 + 3 ....can
2 + 5x...cant

now u can multiply and divide one...u just cant add or subtract them

7 0

2 years ago

1 feet = _____ inches A.2 inches B.12 inches C.1.2 inches D.1 inch

Advocard [28]

Answer:

its B!!!!!!

Step-by-step explanation:

have great day

7 0

2 years ago

Read 2 more answers

A homeowner has an octagonal gazebo inside a circular area. Each vertex of the gazebo lies on the circumference of the circular

Tcecarenko [31]

If we draw the diagonals of the octagonal gazebo, the 4 diagonals divide the octagon into 8 triangles.

Note that each triangle is an isosceles triangle whose equal sides are x, the radius of the circle.

The top angle of each triangle is obtained by dividing the full angle by 8.

So, each top angle = $\frac{360}{8}$

= 45°

Now, in fig., consider one of the triangles Δ OAB. Draw an altitude OC from O to the opposite side AB.

This altitude OC bisects the top angle 45°.

Therefore, ∠ AOC = 22.5°.

Now, in Δ AOC,

$sin 22.5=\frac{AC}{OA}$

$=\frac{AC}{x}$

So, AC = x sin 22.5°

Note that, AB = 2 AC.

Therefore, AB = 2x sin 22.5°.

Also, $cos 22.5=\frac{OC}{OA}$

$=\frac{OC}{x}$

So, OC = x cos 22.5°.

Area of Δ AOB = $\frac{1}{2}(AB)(OC)$

= $\frac{1}{2}$ × (2x sin 22.5°) × (x cos 22.5°)

= $\frac{1}{2} x^{2}$ (2 sin 22.5° cos 22.5°)

= $\frac{1}{2} x^{2}$ sin 45°

= $x^{2}$ / $2\sqrt{2}$

Area of the octagonal gazebo = 8 × one triangular area

= 8 × ( $x^{2}$ / $2\sqrt{2}$ )

$=2\sqrt{2} x^{2}$

$=2.828x^{2}$

Area required for mulch = circular area - area of the gazebo

$=3.14x^{2} -2.828x^{2}$

$=0.312x^{2}$

Now, cost per unit area = $1.50.

Hence, total cost g(m) = area × cost per unit area

Total cost g(m) = $0.312x^{2}$ × 1.5

$=0.468x^{2}$

Hence, total cost g(m) = $0.468x^{2}$ .

4 0

3 years ago

Consider a fictitious company, Teslala, that produces a single type of electronic vehicle, Model Z. The demand for Model Z depen

grin007 [14]

The ratio X/Y for the fictitious company, Teslala, that produces a single type of electronic vehicle, Model Z is 10/pY.

<h3>What is a mathematical model?</h3>

A mathematical model is the model which is used to explain the any system, the effect of the components by study and estimate the functions of systems.

Consider a fictitious company, Teslala, that produces a single type of electronic vehicle, Model Z.

The demand for Model Z depends on the gasoline price (q) because customers tend to purchase an electronic vehicle as a substitute for vehicles that run on gasoline when the gasoline price increases.

The demand for Model Z is estimated as

$D(p) = 180 + 10q - 4p$

Here, <em>p</em> is the price of Model Z.

Consider the following two statements:

1. When the average gasoline price q increases by $1, the revenue-maximizing price p" increases by $X.

$D(p) = 180 + 10q - 4p\\D(p) = 180 + 10(q+1) - 4(p+X)$

2. When the average gasoline price q increases by $1, the demand at the revenue-maximizing price (i.e., D(p*)) increases by a factor of Y.

$D(p)+Y = 180 + 10q - 4p\\(D(p)+Y) = 180 + 10(q+1) - 4(p+X)\\Y= 180 + 10(q+1) - 4(p+X)-D(p)\\$

Put the value of demand at the revenue-maximizing price as,

$Y= 180 + 10(q+1) - 4(p+X)-(180 + 10q - 4p)\\Y= 180 + 10q+10 - 4p-pX-180 - 10q + 4p\\Y= 10 -pX\\1=\dfrac{10}{Y}-\dfrac{pX}{Y}\\\dfrac{10}{Y}=\dfrac{pX}{Y}\\\dfrac{10}{pY}=\dfrac{X}{Y}$

Thus, the ratio X/Y for the fictitious company, Teslala, that produces a single type of electronic vehicle, Model Z is 10/pY.

Learn more about the mathematical model here;

brainly.com/question/4960142

#SPJ1

5 0

1 year ago

If w = 12 units, x = 7 units, and y = 8 units, what is the surface area of the figure? Figure is composed of a right square pyra

bearhunter [10]

Answer:

720 sq units.

Step-by-step explanation:

Length and width of square prism, w = 12 units

Height of square prism, x = 7 units

Height of square pyramid, y = 8 units

Please have a look at the attached image.

Here 2 Surfaces will not be exposed which are base of the square pyramid and the top of the square prism i.e. 2 square surfaces will not be exposed.

Here, surface area of the composite figure will be:

<em>Surface Area of Composite Figure = Lateral surface area of Square Pyramid + Surface Area of 5 surfaces of the square prism</em>

For finding the lateral surface area of pyramid, we need to find the slant height of the pyramid.

Let slant height be $l$ units.

Using pythagoras theorem, we can find out the value of $l$ .

As per theorem:

$Hypotenuse^{2} = Base^{2} + Height^{2}\\$

$\Rightarrow l^{2} = (\dfrac{w}{2})^{2} + y^{2}\\\Rightarrow l^{2} = (\dfrac{12}{2})^{2} + 8^{2}\\\Rightarrow l^{2} = {6}^{2} + 8^{2}\\\Rightarrow l^{2} = 36+64 = 100\\\Rightarrow l = 10\ units$

Lateral surface area of square prism = 4 $\times$ Area of triangular surface

$\Rightarrow 4 \times \dfrac{1}{2}\times Base \times Slant\ Height\\\Rightarrow 4 \times \dfrac{1}{2} \times 10 \times 12\\\Rightarrow 240\ sq\ units$

Surface Area of 5 surfaces of the square prism =

$4 \times x \times w + w^2\\\Rightarrow 4 \times 12 \times 7 + 12^2\\\Rightarrow 336 +144\\\Rightarrow 480\ sq\ units$

So, total surface area of composite figure:

240 + 480 = 720 sq units.

7 0

2 years ago