Given f(x) =x^2 -x and g(x)=3x-4 what is g(f(-3))

A plane contains how many lines? one line two lines three lines infinite number of lines

krok68 [10]

I'm pretty sure it's an infinite number of lines

5 0

3 years ago

Construct a 95% confidence interval to estimate the population mean using the data below. x overbarequals37 sigmaequals10 nequa

kap26 [50]

Answer:

With 95% confidence when n equals 44, the population mean is between a lower limit of 33.96 and an upper limit of 40.04

Step-by-step explanation:

Confidence Interval = mean + or - Error margin (E)

mean = 37

sd = 10

n = 44

degree of freedom = n - 1 = 44 - 1 = 43

t-value corresponding to 43 degrees of freedom and 95% confidence level is 2.0165

E = t × sd/√n = 2.0165×10/√44 = 3.04

Lower limit = mean - E = 37 - 3.04 = 33.96

Upper limit = mean + E = 37 + 3.04 = 40.04

95% confidence interval is between 33.96 and 40.04

7 0

3 years ago

Sachin used synthetic division to divide a polynomial, p(x), by x + 5 and found that there was no remainder. What does this tell

Setler [38]

Answer:

A

Step-by-step explanation:

7 0

2 years ago

The smiths have two children. The sum of their ages is 23. The produce of their ages is 132. How old are the children?

kolezko [41]

For this case we propose a system of equations:

x: Let the variable representing the age of the first child of the Smiths

y: Let the variable representing the age of the second child of the Smiths

According to the data of the statement we have to:

$x + y = 23\\x * y = 132$

From the first equation we have to:

$x = 23-y$

We substitute in the second equation:

$(23-y) * y = 132\\23y-y ^ 2 = 132\\y ^ 2-23y + 132 = 0$

We find the solutions by factoring:

We look for two numbers that, when multiplied, result in 132 and when added, result in 23. These numbers are 11 and 12.

Thus, we have that the factorized equation is:

$(y-11) (y-12) = 0$

Thus, the solutions are: $y_ {1} = 11\\y_ {2} = 12$

So, we can take any of the solutions:

With $y = 11$

Then $x = 23-11 = 12$

Therefore, the ages of the children are 11 and 12 respectively.

Answer:

The ages of the children are 11 and 12 respectively.

6 0

3 years ago

A rectangular playground is to be fenced off and divided in two by another fence parallel to one side of the playground. Four hu

castortr0y [4]

Answer: h = 120 ft; w = 80 ft

A = 9600 ft^2

Step-by-step explanation: Let h and w be the dimensions of the playground. The area is given by:

A = h*w (eq1)

The total amount of fence used is:

L = 2*h + 2*w + w (eq2) (an extra distance w beacuse of the division)

Solving for w:

w = L - 2/3*h = 480 - 2/3*h (eq3) Replacing this into the area eq:

We derive this and equal zero to find its maximum:

Solving for h:

h = 120 ft. Replacing this into eq3:

w = 80ft

Therefore the maximum area is:

A = 9600 ft^2

5 0

3 years ago