Answer:
x = 5
y = 1
Step-by-step explanation:
So move 2y from the second equation to the other side of the equals sign
2x +3y = 13
x = 3 + 2y
From here substitute X into the first equation
2(3 + 2y) + 3y = 13
Distribute
6 + 4y +3y = 13
Combine like terms and solve for y
7y = 7
y = 1
insert result into the original equation.
x-2(1) = 3
x - 2 = 3
x = 5
insert into other equation to check work
2(5) + 3(1) = 13
10 + 3 = 13 correct
Answer:
Option D.
Step-by-step explanation:
The vertex form of an absolute function is
where, a is a constant, (h,k) is vertex.
It is given that, vertex of an absolute function is (2,3). So, h=2 and k=3.
...(1)
It crosses the x-axis at (5,0). So put x=5 and y=0 to find the value of a.
Put a=-1 in (1).
Now, put y=0, to find the equation for this absolute value function when y=0.
Therefore, the correct option is D.
It is D, because you have to get the denomenator"s equal so 9 times 4 is 36 and you take the numerator's and times by the other's denominator then subtract them to get 5/36
Step-by-step explanation:
Use PEMDAS
Probability of an event= number of ways an event can occur / total number of possible outcomes.
Probability = 6/12 = 0.5
