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wel
4 years ago
7

The formula for the volume of a cube is V = s3.

Mathematics
2 answers:
Dmitry [639]4 years ago
8 0

Answer:

The answer is C

Step-by-step explanation:

NemiM [27]4 years ago
5 0

The volume of cube=27 m³

So each side will be=∛27=3m (Answer)

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Determine the degree for the following functions 4x 5 + 3x 2 + 24 23x 3 – 35x 15 + 45x 9
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Answer:

  1. 5
  2. 15

Step-by-step explanation:

We assume your expressions are ...

  4x^5 + 3x^2 + 24

  23x^3 – 35x^15 + 45x^9

The exponents of the variable in the terms of the first expression are ...

  5, 2, 0

The largest of these values is 5, so the first expression has degree 5.

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The exponents of the variable in the terms of the second expression are ...

  3, 15, 9

The largest of these values is 15, so the second expression has degree 15.

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Select the three basic trig ratios.<br> A. sine<br> B. cosine<br> C. tangent<br> D. secant
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Read 2 more answers
Write the standard form of the equation that passes through the point (-2, 4) and is parallel to x - 2y = 6. Include your work i
boyakko [2]

Answer:

The equation of line passing through point ( - 2 , 4) with slope parallel to given line is   y =  \dfrac{1}{2} x + 5

Step-by-step explanation:

Given as :

The equation of line is x - 2 y = 6

Or, 2 y = x - 6

Or, y = \dfrac{1}{2} × x -  \dfrac{6}{2}

i.e y = \dfrac{1}{2} × x -  3

<u>Now, Standard equation of line in slope-intercept form </u>

y = m x + c

where m is the slope of line

And c is the y-intercept

Now, Compare given line with standard line equation

So, The slope of line y = \dfrac{1}{2} × x -  3 = m = \dfrac{1}{2}

<u>Again</u>

Other line is passing through points ( - 2 , 4) and is parallel to given line

∵ For parallel lines condition

The slope of both lines are equal

Let The slope of other line = M

So, from condition

M = m =  \dfrac{1}{2}

<u>Now, equation of line passing through point ( - 2 , 4) with slope   \dfrac{1}{2} </u>

So, Equation of line in slope-point form

y - y_1 = M × (x - x_1)

Or, y - 4 =  \dfrac{1}{2} × (x - ( - 2) )

Or, y - 4 =  \dfrac{1}{2} × (x + 2 )

Or, y = \dfrac{1}{2} × (x + 2 ) + 4

Or, y =  \dfrac{1}{2} × x +  \dfrac{1}{2} × 2 + 4

Or, y = \dfrac{1}{2} × x +  \dfrac{2}{2} + 4

∴   y =  \dfrac{1}{2} × x + 1 + 4

i.e y =  \dfrac{1}{2} x + 5

So, Equation of other line  y =  \dfrac{1}{2} x + 5

Hence, The equation of line passing through point ( - 2 , 4) with slope parallel to given line is   y =  \dfrac{1}{2} x + 5 . Answer

8 0
4 years ago
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