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forsale [732]
3 years ago
12

The area of a playground is 216 yd^2. The width of the playground is 6 yd longer than its length. Find the length and width of t

he playground, including appropriate u its. Show work
Mathematics
1 answer:
zvonat [6]3 years ago
5 0

Let the length of the playground be x, then the width is 6 + x.

Area = length * width = x * (6 + x) = 6x + x^2 = 216

Solving the quadratic equation x^2 + 6x - 216 = 0, we have x = 12 or -18

i.e length = 12 and width = 6 + 18 = 18

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A simple random sample of 110 analog circuits is obtained at random from an ongoing production process in which 20% of all circu
telo118 [61]

Answer:

64.56% probability that between 17 and 25 circuits in the sample are defective.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 110, p = 0.2

So

\mu = E(X) = np = 110*0.2 = 22

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{110*0.2*0.8} = 4.1952

Probability that between 17 and 25 circuits in the sample are defective.

This is the pvalue of Z when X = 25 subtrated by the pvalue of Z when X = 17. So

X = 25

Z = \frac{X - \mu}{\sigma}

Z = \frac{25 - 22}{4.1952}

Z = 0.715

Z = 0.715 has a pvalue of 0.7626.

X = 17

Z = \frac{X - \mu}{\sigma}

Z = \frac{17 - 22}{4.1952}

Z = -1.19

Z = -1.19 has a pvalue of 0.1170.

0.7626 - 0.1170 = 0.6456

64.56% probability that between 17 and 25 circuits in the sample are defective.

4 0
3 years ago
(11 - 8)3 – 2 x 6<br> What is the answer
torisob [31]

Answer:

15

Step-by-step explanation:

3 0
2 years ago
I am in 9th grade,if you have 889,865x999,786 what doe it equal also yes i am not in virtual school and teacher will not let me
RSB [31]

Answer:

889674568890

Step-by-step explanation:

I used a calculator :)

6 0
2 years ago
HELP!!!!In 2004, school lunch Rockwell high school was $2.20.In 2009 the costs increased to $3.25. Find the annual rate of chang
arsen [322]

Answer:

$0.21 per year

Step-by-step explanation:

$0.21 times 5 years equals $1.05

So its $0.21

5 0
3 years ago
The formula for the volume of a sphere is V = Ar3, where Vis the volume
nalin [4]

Answer: 4.7 inches

Step-by-step explanation:

435=4/3(3.14)r³

4 0
3 years ago
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