Question

The area of a playground is 216 yd^2. The width of the playground is 6 yd longer than its length. Find the length and width of the playground, including appropriate u its. Show work

Answer 1

Let the length of the playground be x, then the width is 6 + x.

Area = length * width = x * (6 + x) = 6x + x^2 = 216

Solving the quadratic equation x^2 + 6x - 216 = 0, we have x = 12 or -18

i.e length = 12 and width = 6 + 18 = 18