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3 years ago

When was the midpoint formula discovered?

Mathematics

1 answer:

photoshop1234 [79]3 years ago

3 0

Answer:

$(\frac{x1+x2}{2}, \frac{y1+y2}{2})$

Step-by-step explanation:

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12351 rounded to the nearest hundred explain how you rounded

Nataly_w [17]

$\bf 12,\underline{351}\impliedby \textit{3 hundreds, and 51 units, let's round that}
\\\\\\
\begin{array}{llll}
300----- 50-----400\\
\qquad \qquad \uparrow\qquad \qquad \qquad \uparrow \\

\begin{array}{llll}
anything\ here\\
rounds\ up\ to\\
300
\end{array}\quad
\begin{array}{llll}
anything\ here\\
rounds\ up\ to\\
400
\end{array}
\end{array}
\\\\\\
\textit{therefore, the hundreds value of 300, the 51 tips it over to 400}
\\\\\\
12,\underline{400}$

3 0

3 years ago

Read 2 more answers

Assuming the conditions regarding the motion represented in the graph remain the same, determine the acceleration of the object

vovikov84 [41]

(a)

We can see that

this is a straight line

and this is the graph of velocity

we know that

acceleration is the derivative of velocity

so, slope of curve of velocity is acceleration

so, we will find slope of this line

We can select any two points

(0,4) and (5,7)

we can use slope formula

$m=\frac{y_2-y_1}{x_2-x_1}$

now, we can plug points

$m=\frac{7-4}{5-0}$

$m=0.6$

we know that slope of line is always constant irrespective of any value of t

so, acceleration will always be same irrespective of any value of t

so, we will get acceleration

$a(t)=0.6m/s^2$ ............Answer

(b)

we can see that acceleration is constant

and we know that

derivative of constant is always 0

so, instantaneous rate of acceleration at t=10s is 0........Answer

7 0

3 years ago

Read 2 more answers

Can some help please?!?!

Alexandra [31]

Answer:

<em>Choice D.</em>

Step-by-step explanation:

Vertical line test for functions:

If a vertical line drawn anywhere on the graph intersects the graph in more than one point, it is not a function.

If you draw a vertical line passing through any point between x = -4 and x = 4, the line will intersect two points on the circle. The relation fails the vertical line test. That shows that this relation is not a function.

6 0

3 years ago

-3, -2,-1, 0, 1, 2, 3, are called_______

loris [4]

Answer: Integers

Step-by-step explanation: To help introduce the set

of integers, let's use the number line shown below.

Notice that on a number line, 0 is in the middle, all numbers to the

left of 0 are negative, and all numbers to the right of 0 are positive.

The set of integers includes the set of whole numbers, {0, 1, 2, 3, ...},

which appear at 0 and to the right of 0 on the number line.

The set of integers also includes {-1, -2, -3, ...} which