Answer:
2147.76 cm³
Step-by-step explanation:
using the formula for volume
πr²h
3.14×6²×19
Answer:
A signal from the transmitter will be picked up through out the 57.38 mile drive
Step-by-step explanation:
The radius of the transmitter = 63 miles
Therefore, since both the location 38 miles north and the location 43 miles east of the transmitter are within the the radius, the transmission of the transmitter will be received through out the straight line journey
The length of the travel path is given by;
Distance from 38 miles north of the transmitter to distance of 43 miles east of transmitter =
.
(a) By the fundamental theorem of calculus,
<em>v(t)</em> = <em>v(0)</em> + ∫₀ᵗ <em>a(u)</em> d<em>u</em>
The particle starts at rest, so <em>v(0)</em> = 0. Computing the integral gives
<em>v(t)</em> = [2/3 <em>u</em> ³ + 2<em>u</em> ²]₀ᵗ = 2/3 <em>t</em> ³ + 2<em>t</em> ²
(b) Use the FTC again, but this time you want the distance, which means you need to integrate the <u>speed</u> of the particle, i.e. the absolute value of <em>v(t)</em>. Fortunately, for <em>t</em> ≥ 0, we have <em>v(t)</em> ≥ 0 and |<em>v(t)</em> | = <em>v(t)</em>, so speed is governed by the same function. Taking the starting point to be the origin, after 8 seconds the particle travels a distance of
∫₀⁸ <em>v(u)</em> d<em>u</em> = ∫₀⁸ (2/3 <em>u</em> ³ + 2<em>u</em> ²) d<em>u</em> = [1/6 <em>u</em> ⁴ + 2/3 <em>u</em> ³]₀⁸ = 1024
C=2πr=2(9)π=18π......
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Answer: 6.5%
Step-by-step explanation: