<span>THE AREA OF THE ROOM IS :A=4*2.4=9.6 m^2
THICKNESS t=0.30 m
DIFFERENCE IN TEMPERATURE dT=18-6=12
q=kAdT/dx=kA*dT/t
q=1.3(9.6)(12)/0.30=4992 W=499.2 J/s
In 1 hour or 3600 sec
P=q*T=(499.2 J/s)(3600 s)=1797120 J=1.8 MJ
1.8MJ OF HEAT FLOWS HTROUGH THE WALL IN ONE HOUR</span>
C. -2° :) hope this helps lmk!
R + 75 = 200 . You take away 75 from 200 and r = 125 so 125 is the answer
Answer:
2
Step-by-step explanation:
OMG....this one took me hours to solve...I'm guess 2?
Answer:
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