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Fofino [41]
3 years ago
15

Please help!!! 98 Brainliest Points to anyone who can help with these!!

Mathematics
1 answer:
Talja [164]3 years ago
4 0
The distance between them is 4.0
The equation would be 1.5-(-2.5)=d

Hope that helps?
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Which expression is equivalent to StartRoot 128 x Superscript 8 Baseline y cubed z Superscript 9 Baseline EndRoot? Assume y grea
zepelin [54]

The expression √(128x⁸y³z⁹) is equivalent to the expression 8x⁴yz⁴ √(2yz). Then the correct option is C.

The missing options are given below.

<h3>What is an equivalent expression?</h3>

The equivalent is the expressions that are in different forms but are equal to the same value.

The expression is given below.

⇒ √(128x⁸y³z⁹)

Then the expression is given below.

⇒ √[(64 × 2)(x⁴)²(y²y)(z⁸z)]

⇒ 8x⁴yz⁴ √(2yz)

Then the correct option is C.

More about the equivalent link is given below.

brainly.com/question/889935

#SPJ1

4 0
2 years ago
Look at this graph:<br><br> What are the coordinates of the vertex?
asambeis [7]

Answer:

-1, -1

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the volume of the entire figure to the nearest whole number. Use 3.14 for Pi.
Alja [10]

Answer:

1733.28 m³ or approximately 1733 m³

Step-by-step explanation:

Cone - 1/3πr²h

Cylinder - πr²h

Cone - 1/3(3.14)(6)²(10) ⇒ 376.8

Cylinder - (3.14)(6)²(12) ⇒ 1356.48

1356.48 + 376.8 = 1733.28 m³

Approximately 1733 m³

4 0
4 years ago
A simple random sample of 100 observations was taken from a large population. The sample mean and the standard deviation were de
olga2289 [7]

Answer:

Se=1.2

Step-by-step explanation:

The standard error is the standard deviation of a sample population. "It measures the accuracy with which a sample represents a population".

The central limit theorem (CLT) states "that the distribution of sample means approximates a normal distribution, as the sample size becomes larger, assuming that all samples are identical in size, and regardless of the population distribution shape"

The sample mean is defined as:

\bar X =\frac{\sum_{i=1}^n x_i}{n}

And the distribution for the sample mean is given by:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

Let X denotes the random variable that measures the particular characteristic of interest. Let, X1, X2, …, Xn be the values of the random variable for the n units of the sample.

As the sample size is large,(>30) it can be assumed that the distribution is normal. The standard error of the sample mean X bar is given by:

Se=\frac{\sigma}{\sqrt{n}}

If we replace the values given we have:

Se=\frac{12}{\sqrt{100}}=1.2

So then the distribution for the sample mean \bar X is:

\bar X \sim N(\mu=80,Se=1.2)

5 0
3 years ago
Given cos(O)=3/5 and tan(O)
Valentin [98]

Answer:

Tan(O) = 4/3

Step-by-step explanation:

According to SOH CAH TOA

cos theta = adj/hyp

cosO = 3/4

adj = 3

hyp = 5

Get the opposite

Using pythagoras theorem

opp^2 = hyp^2-adj^2

opp^2 = 5^2 - 3^2

opp^2 = 25-9

opp^2 = 16

opp = 4

Tan (O) = opp/adj

Tan(O) = 4/3

Hence Tan(O) = 4/3

3 0
3 years ago
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