For 3 days....
option 1 : 25(3) + 0.10m = 75 + 0.10m
option 2 : 60(3) = 180
180 < 75 + 0.10m
180 - 75 < 0.10m
105 < 0.10m
105 / 0.10 < m
1050 < m.....this is minutes, we need hrs
1050/60 < m
17.5 < m.......the guest would have to spend more then 17.5 hrs
Hj said he would be a little bit later on Friday and
Assuming 5a3 equals 5a^3, and the same for everything else, you would plug in 4 for a, so 5(4)^3 - 2(4)^2 + 4 - 45, which equals 247.
R is 4 if I'm wrong sorry
