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miv72 [106K]
3 years ago
8

How many solutions are there to this equation 9x+27=9(x+2)+9

Mathematics
1 answer:
lord [1]3 years ago
5 0
Infinitely many sols
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Find the missing factor x^2-11x+18=(x-2)( )
tia_tia [17]
I'd use synthetic div. here, with 2 as my divisor:

      ________________
2   /   1    -11    18
                  2   -18
     ----------------------------
         1     -9      0

Note that the coefficients of the missing factor are given here and are 1 and -9.  Thus, (x-9) is the missing factor.
4 0
3 years ago
Evaluate the expression for the given value of x.<br> 6x + 7 for x = 2<br> The solution is
pav-90 [236]

Answer:

6x + 7

6 * 2

12 + 7

=19

Step-by-step explanation:

4 0
3 years ago
The television show CSI: Shoboygan has been successful for many years. That show recently had a share of 18, meaning that among
jeyben [28]

Answer:

(a) The value of P (None) is 0.062.

(b) The value of P(at least one) is 0.938.

(c) The value of P(at most one) is 0.253.

(d) The event is not unusual.

Step-by-step explanation:

Let <em>X</em> = number of households watching the show.

The probability of the random variable <em>x</em> is, P (X) = <em>p</em> = 0.18.

The sample selected for the survey is of size, <em>n</em> = 14

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 14 and <em>p</em> = 0.18.

The probability of a Binomial distribution is computed using the formula:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,...

(a)

Compute the probability that none of the households are tuned to CSI: Shoboygan as follows:

P(X=0)={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}=1\times1\times0.06214=0.062

Thus, the value of P (None) is 0.062.

(b)

Compute the probability that at least one household is tuned to CSI: Shoboygan as follows:

P (X ≥ 1) = 1 - P (X < 1)

             = 1 - P (X = 0)

             =1-0.062\\=0.938

Thus, the value of P(at least one) is 0.938.

(c)

Compute the probability that at most one household is tuned to CSI: Shoboygan as follows:

P (X ≤ 1) = P (X = 0) + P (X = 1)

             ={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}+{14\choose 1}(0.18)^{1}(1-0.18)^{14-1}\\=0.062+0.191\\=0.253

Thus, the value of P(at most one) is 0.253.

(d)

An event that has a very low probability of occurrence is known as an unusual event.

The probability of the event "at most one household is tuned to CSI: Shoboygan" is 0.253.

This probability value is not low.

Hence, the event is not unusual.

5 0
4 years ago
A scale drawing of jimmy's living room is shown below width =4cm length =6cm
Semenov [28]
Do you need the area of the floor plan? If so here you go:

6*4 = 24, so 24 cm.
7 0
3 years ago
Thor’s hammer can cover 4.95 km in a second. How many kilometers will it cover in 4.95 seconds
valina [46]

Answer:

24.5025

Step-by-step explanation:

4.95 x 4.95=24.5025

Hope I helped!

6 0
3 years ago
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