How is 206×639 different from 8547÷54?

Mathematics

1 answer:

adoni [48]4 years ago

7 0

One is multiplication (206 x 639). The other is division (8547 divided by 54).

Hope this helps xox :)

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The table shows the American League batting champions for the years 1999–2003. The sum of these five batting averages is 1.754.

fgiga [73]

The answer is A. .357 + .372 + .350 + .349 + x = 1.754; .326

x1 - average of 1999 Nomar Garciaparra Boston
x2 - average of 2000 Nomar Garciaparra Boston
x3 - average of 2001 Ichiro Suzuki Seattle
x4 - average of Manny Ramirez Boston
x - average of 2003 Bill Mueller Boston

The sum of these five batting averages is 1.754:
x1 + x2 + x3 + x4 + x = 1.754

From the table:
x1 = 0.357
x2 = 0.372
x3 = 0.350
x4 = 0.349
x = ?

0.357 + 0.372 + 0.350 + 0.349 + x = 1.754

1.428 + x = 1.754
x = 1.754 - 1.428
x = 0.326

5 0

4 years ago

If f(x)=4x^2+1 and g(x)=x^2-5 find(f+g)(x)

Zepler [3.9K]

Answer:

$\large\boxed{(f+g)(x)=5x^2+6}$

Step-by-step explanation:

$(f+g)(x)=f(x)+g(x)\\\\f(x)=4x^2+1,\ g(x)=x^2-5\\\\\text{Substitute:}\\\\(f+g)(x)=(4x^2+1)+(x^2-5)\\\\=4x^2+1+x^2-5\qquad\text{combine like terms}\\\\=(4x^2+x^2)+(1+5)\\\\=5x^2+6$