A. 1/5 B. 1/3 C. 7/15 D. 1/2

Mathematics

1 answer:

Allisa [31]4 years ago

4 0

$P(B|A)=\dfrac{P(A \cap B)}{P(A)}\\\\ |\Omega|=15\cdot14=210\\ |A|=3\cdot14=42\\ |A \cap B|=3\cdot7=21\\\\ P(A)=\dfrac{42}{210}=\dfrac{7}{35}\\ P(A \cap B)=\dfrac{21}{210}=\dfrac{1}{10}\\\\ P(B|A)=\dfrac{\dfrac{1}{10}}{\dfrac{7}{35}}=\dfrac{1}{10}\cdot\dfrac{35}{7}=\dfrac{1}{2}\Rightarrow \text{D}$

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Answer:

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Step-by-step explanation:

Gage Millar, Algebra 2 tutor

(3,5) -> (11, -5) requires a transition of (+8, -10) divide this by 2 to see how much both sides changes (+4, -5) then add this to the original problem , (3,5) to get (7,0)

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Hello!

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PART A:
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Radius (y) (inches): 1 8 11 12

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$\begin{center}
\begin{tabular}
{|c|c|c|c|c|}
x & y & x^2 & y^2 & xy \\ [1ex]
1 & 1 & 1 & 1 & 1\\
4 & 8 & 16 & 64 & 32\\
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\Sigma x=22 & \Sigma y=32 & \Sigma x^2=166 & \Sigma y^2=330 & \Sigma xy=230
\end{tabular}
\end{center}$

Recall that the correlation coefitient is given by the equation:
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From the value of the correlation coeffeicient, it can be deduced that the radius of the algae has a strong positive relationship with the time.

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Therefore, <span>the data in the table represent both correlation and causation.</span>

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Hope this helps. Domain and range are the same for this question.