I believe the answer would be B. 11 because you can see a pattern. Its just skipping.
the answer to 1/3 times 3/4 is 1/4
First list all the terms out.
e^ix = 1 + ix/1! + (ix)^2/2! + (ix)^3/3! ...
Then, we can expand them.
e^ix = 1 + ix/1! + i^2x^2/2! + i^3x^3/3!...
Then, we can use the rules of raising i to a power.
e^ix = 1 + ix - x^2/2! - ix^3/3!...
Then, we can sort all the real and imaginary terms.
e^ix = (1 - x^2/2!...) + i(x - x^3/3!...)
We can simplify this.
e^ix = cos x + i sin x
This is Euler's Formula.
What happens if we put in pi?
x = pi
e^i*pi = cos(pi) + i sin(pi)
cos(pi) = -1
i sin(pi) = 0
e^i*pi = -1 OR e^i*pi + 1 = 0
That is Euler's identity.
Answer:
D. 11.25 students per year
Step-by-step explanation:
<span>(r^2+7r+10/3) * (3r-30/r^2-5r-50)
1/3(3r^2+21r+10) x 3(r-10)/(r^2-5r-50)
(3r^2+21r+10)x(r-10)/(r^2-10r+5r-50)
(3r^2+21r+10)x(r-10)/(r-10)(r+5)
3r^2+21r+10/(r+5)
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