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3 years ago

5

of a class of 32 students ,17 study music and 20 studyart what is the least number of students who could study both music and ar

t

2 answers:

VMariaS [17]3 years ago

5 0

Answer:
5 students could only study both music art

8_murik_8 [283]3 years ago

4 0

Answer:

5

Step-by-step explanation:

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Find a.b. a=2i+j, b=i-j+k

GuDViN [60]

Answer:

$a.b = 1$

Step-by-step explanation:

We are given the following in the question:

$a=2i+j\\b=i-j+k$

We have to find the dot product.

Formula:

$a = x_1i + x_2j + x_3k\\b = y_1i + y_2j + y_3k\\a.b = x_1y_1 + x_2y_2 + x_3y_3$

Putting the corresponding values we get,

$a.b = (2.1) + (1.-1) + (0.1)\\= 2-1+0\\=1$

$a.b = 1$

5 0

4 years ago

Solve for p. G=8/5(p-4)

Archy [21]

Answer:

$\large\boxed{p=\dfrac{5G+32}{8}}$

Step-by-step explanation:

$\dfrac{8}{5}(p-4)=G\qquad\text{multiply both sides by 5}\\\\8(p-4)=5G\qquad\text{use distributive property}\\\\8p-32=5G\qquad\text{add 32 to both sides}\\\\8p=5G+32\qquad\text{divide both sides by 8}\\\\p=\dfrac{5G+32}{8}$

6 0

3 years ago

I need help with this.<br> Find the surface area of each 3D figure below.

Bess [88]

Answer:2300 cm2

Step-by-step explanation:

First you want to divide 350 by 14. You get 25. Now multiply 25 x 26 and then divided by 2. Once you get that answer, multiply that 5 times since there is 5 triangles. Then, add that to the base area. Hopefully this is the right answer. let me know if it is.

5 0

3 years ago

Who can answer this question is you get it right ill mark you the brainliest

sp2606 [1]

Answer:

6+11

Step-by-step explanation:

the negative signs cancel out

8 0

3 years ago

Read 2 more answers

Sin A tan A/ 1 - cos A = 1+ sec A

aalyn [17]

$\text{L.H.S}\\\\=\dfrac{\sin A \tan A}{1- \cos A}\\\\\\=\dfrac{\sin A \cdot \tfrac{\sin A}{\cos A} }{ 1- \cos A}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~;\left[\tan A = \dfrac{\sin A }{\cos A}\right]\\\\\\=\dfrac{\tfrac{\sin^2 A}{ \cos A}}{1- \cos A}\\\\\\=\dfrac{\sin^2 A}{\cos A(1-\cos A)}\\\\\\=\dfrac{1-\cos^2 A}{\cos A( 1- \cos A)}~~~~~~~~~~~~~~~~~~~~~~~~;[\sin^2 A + \cos^2 A = 1]\\\\\\$

$=\dfrac{(1+ \cos A)(1 - \cos A)}{\cos A(1 - \cos A)}\\\\\\=\dfrac{1+ \cos A}{ \cos A}\\\\\\=\dfrac{1}{\cos A} + \dfrac{\cos A}{ \cos A}\\\\\\=\sec A + 1 \\\\\\=1+ \sec A\\\\\\=\text{R.H.S}\\\\\text{Proved.}$

8 0

2 years ago