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Yakvenalex [24]
3 years ago
11

together Xavier,Yolanda,and Zachary have $4.44 . if each person has the same amount , how much money does each person have?

Mathematics
2 answers:
Anarel [89]3 years ago
4 0
$1.48 because $4.44 divided by 3 equals $1.48
Snowcat [4.5K]3 years ago
3 0
If their are 3 of them and they all have the same amount, and the finishing total is $4.44, Then they would each have $1.48. If you need the work take $4.44 and divide it by 3.
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A retangle has a perimeter (p) of 58 inches. The length (L) is one more than 3 times the width (W)
worty [1.4K]

The rectangle has a perimeter P of 58 inches.The length l is one more than 3 times the width w.write and solve a system of linear equations to find the length and width of the rectangle?

Answer:

Length(L)=22 inches

Width(W) = 7 inches

Step-by-step explanation:

GIven:-

Perimeter (p)=58 inches,

Length(L)= one more than 3 times the width(W)

Let, W=x   ---------------------------------(equation 1

L=3x+1  -----------------------(equation 2)

Here x is unknown and to find the Width(W) we have to find the value of x.

Now,

Perimeter of rectangle(p) = 2 times length(L) + 2 times width(W)

p=2L+2W

p=2(3x+1)+2x  ----------------(from equation 1)

58=6x+2+2x   ----------------(given p=58 inches)

58=8x+2

8x=58-2

8x=56

x=\frac{56}{8}

x=7          ----------------------(equation 3)

Now substituting the value of equation 3 in equation 2.

L=3x+1

L=(3\times 7)+1

L=21+1

L=22

L=22 inches

as, W=x   -----------------------(from equation 1)

W=7 inches -------------------(equation 3)

Therefore, Length(L) = 22 inches and Width(W) = 7 inches.

7 0
3 years ago
The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6
viktelen [127]

Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

b)

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5.

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders    No. contracts     Relative frequency of contracts

2                         6                       6/102=0.0588

3                         20                     20/102=0.1961

4                         24                     24/102=0.2353

5                         18                       18/102=0.1765

6                         13                        13/102=0.1275

7                          7                          7/102=0.0686

8                          5                          5/102=0.049

9                          6                          6/102=0.0588

10                         2                           2/102=0.0196

11                          1                            1/102=0.0098

Total                  102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved  between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved  strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10=  Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

8 0
3 years ago
$49 jeans are 20% off, what is the sale price
madam [21]

Answer:

$39.2

Step-by-step explanation:

The sale price will be 20% of $49 subtracted from $49

That’s

20% /100% x $49

0.2 x $49

$9.8

Sale price = $49 - $9.8

= $39.2

The sale price is $39.2

8 0
3 years ago
Read 2 more answers
Solve for equation for ex in term of c 2/3(x+1/2) - 1/4=5/2
serg [7]

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4 0
3 years ago
Which one should I choose
Vesna [10]

Answer:

exponential growth 3%

Step-by-step explanation:

3 0
3 years ago
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