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iren [92.7K]
3 years ago
5

You start driving south for 2 miles, turn left, and drive east for another 9 miles. At the end of driving, what is your straight

line distance from your starting point? Round to the nearest tenth of a mile.
Mathematics
2 answers:
TEA [102]3 years ago
7 0

Answer:

Step-by-step explanation:

yulyashka [42]3 years ago
4 0
Use the Pythagorean Theorem: .

So your straight line distance is 10.

We can also recognize this as a multiple of the 3-4-5 Pythagorean triple. We have , with x being the desired value. Therefore x=10, like previously.
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You select a card at random from the cards that make up the word “replacement”. Without replacing the card, you choose a second
natta225 [31]
To find the total probability, we first need to solve for the probability of the individual events.

Event 1:
P(consonant)=7/11
We know this to be true because out of the 11 total possibilities for the event, 7 of them are consonants.
R E P L A C E M E N T 


Event 2
P(e)=3/10
We know this to be true because out of the 10 total possibilities for the event (since we didn't replace the first card we withdrew), 3 of them are the letter 'e'.
R E P L A C E M E N T (-1 to account for the first card we withdrew)

The possibility of both events...

P(consonant then 'e')=7/11*3/10=21/110

Answer: P=21/110
6 0
2 years ago
in a certain pentagon, the interior angles are a,b,c,d,e where a,b,c,d,e are integers strictly less than 180. ("Strictly less th
guajiro [1.7K]

Answer:

  least to greatest: {61, 61, 61, 178, 179}

Step-by-step explanation:

If the third-largest angle is 61°, the smallest three angles cannot be larger than 183°. Since the total of all angles must be 540°, and the total of the largest two cannot be greater than 179°×2 = 358°, the sum of the smallest three must be at least 540° -358° = 182°.

So, the possible sets of angles with the smallest 3 totaling 182° or 183° are (in degrees) ...

  {60, 61, 61, 179, 179} . . . . two modes

  (61, 61, 61, 178, 179} . . . . . one mode -- the set you're looking for

3 0
3 years ago
Read 2 more answers
Identify the segment bisector of XY.
Ganezh [65]

Given the image attached, the segment bisector that divides XY into two and the length of XY are as follows:

  • Segment bisector of XY = line n
  • Length of XY = 6

<em><u>Recall:</u></em>

  • A line that divides a segment into two equal parts is referred to as segment bisector.

In the diagram attached below, line n divides XY into XM and MY.

Thus, the segment bisector of XY is: line n.

<em><u>Find the value of x:</u></em>

XM = MY (congruent segments)

  • Substitute

5x + 8 = 9x + 12

  • Collect like terms and solve for x

5x + 8 = 9x + 12\\5x - 9x = -8 + 12\\\\-4x = 4\\\\x = -1

XY = XM + MY

XY = 5x + 8 + 9x + 12

  • Plug in the value of x

XY = 5(-1) + 8 + 9(-1) + 12\\\\XY = -5 + 8 -9 + 12\\\\\mathbf{XY = 6}

Therefore, given the image attached, the segment bisector that divides XY into two and the length of XY are as follows:

  • Segment bisector of XY = line n
  • Length of XY = 6

Learn more here:

brainly.com/question/19497953

3 0
2 years ago
Which describes the combined variation shown in the equation F= kxy/z ?
DiKsa [7]

Answer:

when the rest of the variables are held constant

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s
Nataliya [291]

Answer:

f(x)=\frac{1}{2}x^2-4x+5

Step-by-step explanation:

A parabola is written in the form

f(x)=a((x-h)^2+k) (1)

where:

h is the x-coordinate of the vertex of the parabola

ak is the y-coordinate of the vertex of the parabola

a is a scale factor

For the parabola in the problem, we know that the vertex has  coordinates (4,-3), so we have:

h=4 (2)

ak=-3

From this last equation, we get that a=\frac{-3}{k} (3)

Substituting (2) and (3) into (1) we get the new expression:

f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3 (4)

We also know that the parabola  contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6

So we also get:

a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}

So the equation of the parabola is:

f(x)=\frac{1}{2}((x-4)^2 -6) (5)

Now we want to rewrite it in the standard form, i.e. in the form

f(x)=ax^2+bx+c

To do that, we simply rewrite (5) expliciting the various terms, we find:

f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5

6 0
3 years ago
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