Solve by completing the square X squared -6x+8=0

1 answer:

8 0

$x^2 -6x+8=0\\\\x^2-2x -4x+8=0 \\\\x(x -2 ) -4(x-2 )=0\\\\ (x -2 ) (x-4 )=0\\ \\x-2=0 \ \ or \ \ x-4=0\\\\x=2 \ \ or \ \ x=4$

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