The answer is 5a. 3a- 4a is -1 then you add -1 and 6, and your outcome comes out to be 5a.
Initially there were 12 dogs
dogs left at the end of day =4
number of dogs sold=12-4=8
price of one dog=$104
price of 8 dogs = 104*8= $832
initially there were 8 cats
cats left at the end of day =5
number of cats sold =8-5=3
price of one cat= $25
price of 3 cats =25*3= $75
ratio of sales for dogs to cats = 832/75
Answer:
P(I⋂D)
Step-by-step explanation:
The symbolic way to represent the probability of a true positive is P(I⋂D).
We know that I stands for Infected, U stands for Uninfected, D for Infection detected, N for infection no detected.
Then, a true positive will be given by the intersection of Infected and Infection Detected.
Hey there!
In order to solve this, remember PEMDAS. First, start with solving whatever is in parentheses. Then, move on to exponents. Then, complete the multiplication and division. Lastly, add or subtract anything remaining. Omit any steps that aren't present.
Parentheses:
<span>1 – 5 + 1 × (4 × 4 – 31) × 8
</span>1 – 5 + 1 × (–15) × 8
Multiplication/Division (Left to Right):
1 – 5 + (–15) × 8
1 – 5 + (–120)
1 – 5 – 120
Addition/Subtraction (Left to Right):
–4 – 120
–124
Your answer is –124.
Hope this helped you out! :-)
7 squared = 49 and 9 squared= 81 add up 49 and 81 and you get 130
