PLEASE HELP!!!! Explain why a quadratic equation with a positive discriminant has two real solutions, a quadratic equation with
1 answer:
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Answer:
Pythagorean triplet are the values of hypotenuse, base and perpendicular which tend to represent a right-angled triangle. Integral solutions to the Pythagorean Theorem, a2+b2=c2 are called Pythagorean triplet which contains three positive integers a,b,c where a<b<c.
Let's say the numbers are "a" and "b"
hmm say "a" is the smaller, and "b" the greater
so "b" is "4 more than 5 times" "a"
so... 5 times "a" is 5*a or 5a
4 more than "that", will be "that" + 4
or
5a + 4
so.. whatever "a" is, "b" is 5a+4
now, their sum is 22, as opposed to "zz" hehe
so
solve for "a", to see what the smaller one is
what's "b"? well, b = 5a + 4
hmm say "a" is the smaller, and "b" the greater
so "b" is "4 more than 5 times" "a"
so... 5 times "a" is 5*a or 5a
4 more than "that", will be "that" + 4
or
5a + 4
so.. whatever "a" is, "b" is 5a+4
now, their sum is 22, as opposed to "zz" hehe
so
solve for "a", to see what the smaller one is
what's "b"? well, b = 5a + 4