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FrozenT [24]
3 years ago
5

PLEASE HELP!!!! Explain why a quadratic equation with a positive discriminant has two real solutions, a quadratic equation with

a negative discriminant has no real solution, and a quadratic equation with a discriminant of zero has one real solution.
Mathematics
1 answer:
Sergeu [11.5K]3 years ago
3 0

Hey there! I'm happy to help!

In the quadratic formula, the discriminant is square rooted. In this formula you have a ± before this radical. If the discriminant is positive, the solution can be either subtracting or adding the number, so there are 2 real solutions.

If it is 0, subtracting or adding are the same, so there will be just one solution.

You cannot have a negative square root. It is impossible with real numbers, so there are no real solutions.

I hope that this helps! Have a wonderful day! :D

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Which solution to the equation 1/x-1 = x-2/2x^2-2 is extraneous
melamori03 [73]

<u>Solution-</u>

The equation given here,

\frac{1}{x-1} =\frac{x-2}{2x^2-2}

\Rightarrow 2x^2-2=(x-1)(x-2)

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3 0
4 years ago
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