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FrozenT [24]
4 years ago
5

PLEASE HELP!!!! Explain why a quadratic equation with a positive discriminant has two real solutions, a quadratic equation with

a negative discriminant has no real solution, and a quadratic equation with a discriminant of zero has one real solution.
Mathematics
1 answer:
Sergeu [11.5K]4 years ago
3 0

Hey there! I'm happy to help!

In the quadratic formula, the discriminant is square rooted. In this formula you have a ± before this radical. If the discriminant is positive, the solution can be either subtracting or adding the number, so there are 2 real solutions.

If it is 0, subtracting or adding are the same, so there will be just one solution.

You cannot have a negative square root. It is impossible with real numbers, so there are no real solutions.

I hope that this helps! Have a wonderful day! :D

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Answer:

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Step-by-step explanation:

Consider a random variable <em>X</em> that follows a Binomial distribution with parameters, sample size <em>n </em>and probability of success <em>p</em>.

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Then the confidence interval for the population proportion <em>p</em> is:

CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }

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Compute the critical value as follows:

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For <em>z</em> = 2.58 the P (Z < z) = 0.995.

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