V = s²h
<span>150 = s²h </span>
<span>150 = s²(3/2)s </span>
<span>(2/3)150 = s³ </span>
<span>100 = s³ </span>
<span>s = ∛100 (approx 4.642 in) </span>
2x-7+-6x-3 2x+-6x=-4x
-4x-10=0
-5/2 is the answer
Answer:
D
Step-by-step explanation:
End behaviour refers to the asymptotes, which both exponential functions have the same one at y = 2. However, they have different y - intercepts. The first one has a y - intercept of 4 and the second one has a y - intercept of 6. Thus, the answer is D.
Answer:
Both angles have a measure of 134degrees, y = 27degrees.
Step-by-step explanation:
As per what is given in the problem:
There are 2 parallel lines, both are intersected by a transversal.
Remember the theorem, when two parallel lines are intersected by a transversal, then the alternate exterior angles are congruent.
The is meanse that:
3y + 53 = 7y - 55
Solve using inverse operations:
3y + 53 = 7y - 55
+55 +55
3y + 108 = 7y
-3y -3y
108 = 4y
/4 /4
27 = y
Now, substitute back in to find the value of the angle:
3y + 53
y = 27
3 ( 27 ) + 53
81 + 53
= 134
Since the angles are alternate exterior, they are congruent, hence both angles have a measure of 134degrees.
