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Tanya [424]
4 years ago
14

F(x)= 2lxl? (graphing absolute values) I'm a little confused.

Mathematics
2 answers:
Vesnalui [34]4 years ago
6 0
I see. Imagine you have f(x)=|x|. It's a V shaped graph.

Now if f(x)=|x|, 2f(x)=2|x|.

Graph Transformation Rule:

af(x), multiply y-coordinates by a.

*Ultimately, you'd still have a V shaped graph in 2f(x)=2|x|, but the y values of all the coordinates in f(x)=|x| would have to be multiplied by 2 giving you 2f(x)=2|x|.
Pani-rosa [81]4 years ago
3 0
F(x) = 2|x| = |2x|

Draw a graph y = 2x
for x = 0 ⇒ y = 2 × 0 = 0 ⇒ (0;0)
for x = 2 ⇒ y = 2 × 2 = 4 ⇒ (2;4)

next:
<span>we turn symmetrically part of the graph below <span>the x-axis</span></span>

Look at the pictures.

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The real part of a complex number z=a+bi is ‘a’, and the imaginary part is ‘b’
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3 years ago
Given the graph of f(x), find each of the following:
Y_Kistochka [10]

The value of the function at x = -1, 0, 1, 2, and 3 will be -4, 3, 2, -1, and 0, respectively.

<h3>What is a function?</h3>

A function is an assertion, concept, or principle that establishes an association between two variables. Functions may be found throughout mathematics and are essential for the development of significant links.

From the graph of f(x), then the value of the function at x = -1, 0, 1, 2, and 3 will be given as,

x             f(x)                        Feedback

-1             -4               Point is in the fourth quadrant

0              3                      Point is in the y-axis

1               2               Point is in the first quadrant

2             -1               Point is in the second quadrant

3              0                      Point is in the x-axis

More about the function link is given below.

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5 0
1 year ago
WILL MARK YOU BRAINLESTA games shop sells marbles
Otrada [13]
The answer is

The diameter is 4 (2) = 8 and height is 10(2) = 20

For the sides, use area of a cylinder = ph

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Area = pi r^2 = 16 pi (times 2 circles) = 32 pi sq cm
5 0
3 years ago
(10 pts) (a) (2 pts) What is the difference between an ordinary differential equation and an initial value problem? (b) (2 pts)
laiz [17]

Answer:

Step-by-step explanation:

(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.

(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.

(C) Example of a second order linear ODE:

M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)

The equation will be homogeneous if K(t)=0 and heterogeneous if K(t)\neq 0

Example of a second order nonlinear ODE:

Y=-3K(Y){2}

(D) Example of a nonlinear fourth order ODE:

K^4(x) - \beta f [x, k(x)] = 0

4 0
3 years ago
Find y as a function of x if y"' + 9y' = 0, y(0) = 6, y'(0) = 9, y"(0) = 18. y(x) =
Andreas93 [3]

Answer:

y(x) = 8 - 2cos 3x + 3sin 3x

Step-by-step explanation:

Given the equation:

y''' + 9y' = 0

The characteristic equation :

⇒r³ + 9r =0

Solving for r, we get r = 0 and r = ± 3i

The general equation for such equation is :

<u>y = C₁ + C₂cos 3x + C₃sin 3x</u>

Given:

y(0) = 6

Thus, Applying in the above equation, we get

<u>6 = C₁ + C₂ .......................................................1</u>

Differentiating y , we get:

<u>y' = -3C₂sin 3x + 3C₃cos 3x</u>

Given:

y'(0) = 9

Thus, Applying in the above equation, we get

<u>9 = 3C</u><u>₃</u>

or,

<u>C</u><u>₃</u><u> = 3</u>

Differentiating y' , we get:

<u>y'' = -9C₂cos 3x - 9C₃sin 3x</u>

Given:

y''(0) = 18

Thus, Applying in the above equation, we get

<u>18 = -9C</u><u>₂</u>

or,

<u>C</u><u>₂</u><u> = -2</u>

Applying in equation 1 , we get:

<u>C₁ = 8</u>

Thus,

<u>y(x) = 8 - 2cos 3x + 3sin 3x</u>

4 0
3 years ago
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