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Trava [24]
3 years ago
9

Heather is saving for retirement and has been doing a lot of research on how much she should put aside each month. The newest ar

ticle says that 1 36 of her salary should be put into a retirement account. If she makes $63,000 a year, how much will she put into her retirement account each month (rounded to the nearest dollar)?
Mathematics
1 answer:
tino4ka555 [31]3 years ago
6 0
If Heather puts in 1.36% of her salary into a retirement account and she makes $63,000 in a year, this can be solved by 1.36% x 63000. First convert 1.36% into a decimal. To do this, divide by 100.

1.36/100=0.0136

1.36% x 63000
=0.0136 x 63000
=856.8
Heather would put $856.8 in for the whole year. To find how much per month, divide by 12.

856.8/12=71.<span>4
</span>Rounded to the nearest dollar is $71.

Heather would put $71 into a retirement account each month.
<em>
</em><em>Note: This was solved by multiply the percent and then dividing by 12 months. You could also do this by dividing by 12 months first and then multiplying the percent.</em>


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3 years ago
What is the square root of m^6?
Nastasia [14]
Answer:
If m is nonnegative (ie not allowed to be negative), then the answer is m^3
If m is allowed to be negative, then the answer is either |m^3| or |m|^3

==============================

Explanation:

There are two ways to get this answer. The quickest is to simply divide the exponent 6 by 2 to get 6/2 = 3. This value of 3 is the final exponent over the base m. Why do we divide by 2? Because the square root is the same as having an exponent of 1/2 = 0.5, so
sqrt(m^6) = (m^6)^(1/2) = m^(6*1/2) = m^(6/2) = m^3
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---------------------------

A slightly longer method is to break up the square root into factors of m^2 each and then apply the rule that sqrt(x^2) = x, where x is nonnegative

sqrt(m^6) = sqrt(m^2*m^2*m^2)
sqrt(m^6) = sqrt(m^2)*sqrt(m^2)*sqrt(m^2)
sqrt(m^6) = m*m*m
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where m is nonnegative

------------------------------

If we allow m to be negative, then the final result would be either |m^3| or |m|^3. 

The reason for the absolute value is to ensure that the expression m^3 is nonnegative. Keep in mind that m^6 is always nonnegative, so sqrt(m^6) is also always nonnegative. In order for sqrt(m^6) = m^3 to be true, the right side must be nonnegative.

Example: Let's say m = -2
m^6 = (-2)^6 = 64
sqrt(m^6) = sqrt(64) = 8
m^3 = (-2)^3 = -8
Without the absolute value, sqrt(m^6) = m^3 is false when m = -2

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And that's how I got my answer. Even further, I took the test and got it right.

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