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AveGali [126]
3 years ago
9

After modifying a numbered list in her presentation, Su notices the numbers and the text are too close to each other. She knows

she can solve this issue by using the hanging indent marker. Unfortunately, the ruler is not visible in her PowerPoint workspace.
Which tab and command group should she use to access the ruler? (View, Show or Insert, Add-ins or Home, Paragraph)
After selecting the numbered list, in which direction should she drag the hanging indent marker to increase the space between the numbers and the text? (upward or downward or to the left or to the right)
Computers and Technology
1 answer:
IrinaK [193]3 years ago
8 0

Answer:

1. View, show

2. to the right

Explanation:

On edg

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Two routers, R1 and R2, connect using an Ethernet over MPLS service The service provides point-to-point service between these tw
liberstina [14]

Answer: b) R1 will connect to a physical Ethernet link, with the other end of the cable connected to a device at the WAN service provider point of presence.

.d) R1 will forward data link frames to R2 using an Ethernet header/trailer.

Explanation:

Here we have to understand what is MLPS. MLPS is a protocol which identifies the shortest route for the transfer of messages between routers instead of the longest route.

Here we are given a WAN which is a wide area network. Using layer 2 Ethernet service the frames are transmitted across the routers within the WAN.

Option A is incorrect as as connecting the other end of the cable to the R2 would reduce the functionality of the WAN.  Option C is incorrect as HDLC header trailer has no effect.

Option B and D are correct as Ethernet header/ trailer has the same size every frame and to maintain the functionality of the WAN one end must be connected to point of presence(PoP).  

5 0
3 years ago
What is the data rate of a DS0 signal?
djyliett [7]

Answer: 64 Kbps

Explanation:

3 0
3 years ago
A(n) ______ network is a system that attempts to imitate the behavior of the human brain. Group of answer choices advanced neura
larisa [96]

Answer:

Neural Networks

Explanation:

Neural networks are networks that mimic the behaviour of the human brain in which they tend to perform a task without been programmed with the task rule, although the neural network are artificial in nature and they often recognize patterns.

Neutral network have cell that enable them to carry out task together in order to produce a desired result and the cell can only solve a little part of tasks.

6 0
3 years ago
I have six nuts and six bolts. Exactly one nut goes with each bolt. The nuts are all different sizes, but it’s hard to compare t
juin [17]

Answer:

Explanation:

In order to arrange the corresponding nuts and bolts in order using quicksort algorithm, we need to first create two arrays , one for nuts and another for bolts namely nutsArr[6] and boltsArr[6]. Now, using one of the bolts as pivot, we can rearrange the nuts in the nuts array such that the nuts on left side of the element chosen (i.e, the ith element indexed as nutArr[i]) are smaller than the nut at ith position and nuts to the right side of nutsArr[i] are larger than the nut at position "I". We implement this strategy recursively to sort the nuts array. The reason that we need to use bolts for sorting nuts is that nuts are not comparable among themselves and bolts are not comparable among themselves(as mentioned in the question)

The pseudocode for the given problem goes as follows:

// method to quick sort the elements in the two arrays

quickSort(nutsArr[start...end], boltsArr[start...end]): if start < end: // choose a nut from nutsArr at random randElement = nutsArr[random(start, end+1)] // partition the boltsArr using the randElement random pivot pivot = partition(boltsArr[start...end], randElement) // partition nutsArr around the bolt at the pivot position partition(nutsArr[start...end], boltsArr[pivot]) // call quickSort by passing first partition quickSort(nutsArr[start...pivot-1], boltsArr[start...pivot-1]) // call quickSort by passing second partition quickSort(nutsArr[pivot+1...end], boltsArr[pivot+1...end])

// method to partition the array passed as parameter, it also takes pivot as parameter

partition(character array, integer start, integer end, character pivot)

{

       integer i = start;

loop from j = start to j < end

       {

check if array[j] < pivot

{

swap (array[i],array[j])

               increase i by 1;

           }

 else check if array[j] = pivot

{

               swap (array[end],array[j])

               decrease i by 1;

           }

       }

swap (array[i] , array[end])

       return partition index i;

}

7 0
3 years ago
If an M:N relationship is mandatory on both sides, and if both relations resulting from the entities involved in the relationshi
vivado [14]

Answer:

0

Explanation:

In the problem above, the relationship that exists between M and N is discovered to be on each side of the system. Furthermore, it was stated that the outcome of the relationship also has approximately 3 records. This shows that there is no record for the bridge that is formed as a result of the relationship.

4 0
3 years ago
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