Answer:
so so sorry I don't know
Explanation:
hope fully you'll get the answer
Answer:
Latency of an object O is shown below.
Explanation:
W segment and stalled state transmits nothing and waits for acknowledgement. The latency is 2 R TT + the time required for server that are using to transmit the object + the amount of time when server is in stalled state. Let K be the number of window that is K= O/WS .The serveries stalled state where K-1 is period of ime with period lasting RTT-(W-1)S/R
latency = 2RTT +O/R +(K-1)[S/R +RTT - WS/R]
After combining the two case
latency = 2 RTT + O/R + (K-1)[S/R +RTT - WS/R]
where [x] means maximum of (x.0). This is the complete ananlysis of the static windows.
server time for transmit the object is (K-1)[S/R +RTT - WS/R]
Answer:
usable capacity = 10 GB
Number of cylinders = 256
Block size = 4 KB
(1)Bytes in each cylinder = (10*230)/(256) = (10*222) = 40 MegaBytes
(2)Number of Blocks in each cylinder = (10*222)/(212) = 10K
(3)capacity of one track = 40 MegaBytes/(10*2) = 2 MB
Rotation speed = 3840 RPM
Number of rotations per second = 3840/60 = 64
Transfer rate = (2*64) = 128 MB/sec
Explanation:
Answer:
Provide the basic interface for the hardware.
Explanation:
