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liraira [26]
3 years ago
12

Queuing delay can vary from packet to packet. Therefore, we use a statistical measure to characterize this delay. True False

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
7 0

Answer:

True

Step-by-step explanation:

Queing delay occurs and varies from packet to packet due to HIGH TRAFFIC,

PROPAGATION DELAY and PROCESSING DELAY

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The radius of a circle is 5 miles. What is the angle measure of an arc bounding a sector with area 10​ square miles?
Lana71 [14]
10÷((22/7)×5^2))
=0.127
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3 years ago
Factories 54m3n + 81m4n2 b) 15x2y3z + 25x3y2z + 35x2y2z​
Oliga [24]

<u>Part a)</u>

Given the expression

54m^3n\:+\:81m^4n^2

Apply exponent rule:    a^{b+c}=a^ba^c

54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn     ∵ m^4n^2=m^3mnn

Rewrite 81 as 3 · 27

Rewrite 54 as 2 · 27

                             =2\cdot \:27m^3n+3\cdot \:27m^3mnn

Factor out the common term:   27m³n

                              =27m^3n\left(2+3mn\right)      

Therefore,

54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn=27m^3n\left(2+3mn\right)

<u>Part B)</u>

Given the expression

15x^2y^3z+25x^3y^2z+35x^2y^2z

Apply exponent rule:    a^{b+c}=a^ba^c

15x^2y^3z+25x^3y^2z+35x^2y^2z=15x^2y^2yz+25x^2xy^2z+35x^2y^2z

Rewrite as

                                               =3\cdot \:5y^2x^2zy+5\cdot \:5y^2x^2zx+7\cdot \:5y^2x^2z

Factor out common term 5y²x²z

                                                =5y^2x^2z\left(3y+5x+7\right)

Therefore,

15x^2y^3z+25x^3y^2z+35x^2y^2z=5y^2x^2z\left(3y+5x+7\right)

8 0
3 years ago
Please help i need this done QUICK im timed ill give the best answer brainliest
seraphim [82]

Answer:

x=−32/5

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

1/2(1/4x−3/5)=1/4(2/5+3/4x)

(1/2)(1/4x)+(1/2)(−3/5)=(1/4)(2/5)+(1/4)(3/4x)(Distribute)(1/2)(1/4x)+(1/2)(−3/5)=(1/4)(2/5)+(1/4)(3/4x)(Distribute)

1/8x+−3/10=1/10+3/16x

1/8x+−3/10=3/16x+1/10

Step 2: Subtract 3/16x from both sides.

1/8x+−3/10−3/16x=3/16x+1/10−3/16x

−1/16x+−3/10=1/10

Step 3: Add 3/10 to both sides.

−1/16x+−3/10+3/10=1/10+3/10

−1/16x=2/5

Step 4: Multiply both sides by 16/(-1).

(16/−1)*(−1/16x)=(16/−1)*(2/5)

x=−3/25

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a relay team of 4 people runs 3 mile. it each person runs the same distance, how many miles does each person run?
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Each person runs 3/4 miles.
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A large pool has a faucet to allow water to enter the pool and a drain to allow water to leave the pool.
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Answer:

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Step-by-step explanation:

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