The answer is 3x^2-19x+1
(-4x+3)-(7x-3x^2-1)
-12x+7x+3x^2+1
Combine like terms:
3x^2+(-12x+-7x)+1
= 3x^2+-19x+1
There you go. cube root of smth is just the value to the power of one third.
1. since the equations equal each other
2x+19=x+7
-x -x
x+19=7
-19 -19
x= -12
sub into y= x+7
y= -12+7
y= -5
2. x+2y=-7
<span>x+y+23=0
i don't know what the second equation is equal to, i'll assume 0
2y=x-7
y=1/2x-7/2
sub this into x+y+23=0
x+1/2x-7/2+23=0
3/2x+39/2=0
-39/2 -39/2
3/2x= -39/2
x=-39/2 / 3/2
x= -13
sub into y=1/2x-7/2
y=1/2(-13)-7/2
y= -10
3. </span>x+5y=2
<span>x=-4y+5
</span>sub x=-4y+5 into x+5y=2
-4y+5+5y=2
y+5=2
-5 -5
y= -3
sub y =-3 into x =-4y+5
x=-4(-3)+5
x= 17
4. 3x+y=9
<span>y=-5x+9
</span>sub -5x+9 into 3x+y=9
3x+(-5x+9)=9
3x-5x+9=9
-2x+9=9
-9 -9
-2x=0
x=0
sub into y=-5x+9
y=-5(0)+9
y=9
To round this we have to go to the thousands place since the thousands place in this question is 8 its closer to 10 so the answer is 10k or 10,000
Let x = number of adult tickets, and y = number of children tickets. One equation must deal with the number of tickets, and the other equation must deal with the revenue from the tickets.
Then x + y = 300 is the number of tickets
12x + 8y = 3280 is the revenue from the tickets.
Using the substitution method:
x + y = 300 ⇒ y = 300 - x ⇒ Equation (3)
12x + 8y = 3280 ⇒ 12x + 8(300-x) = 3280 ⇒ x = 220
y = 300 - x ⇒ y = 300-220 ⇒ 80
Therefore 220 adult tickets and 80 children's tickets were sold.
