11/21 would be the answer
        
             
        
        
        
1. 13/3m
2. 24m to the 2nd power over 3 m
3.72 m to the 2nd power -11 over 3m
4.-16/3m
        
             
        
        
        
The solution to the given differential equation is yp=−14xcos(2x)
The characteristic equation for this differential equation is:
P(s)=s2+4 
The roots of the characteristic equation are:
s=±2i 
Therefore, the homogeneous solution is:
yh=c1sin(2x)+c2cos(2x) 
Notice that the forcing function has the same angular frequency as the homogeneous solution. In this case, we have resonance. The particular solution will have the form:
yp=Axsin(2x)+Bxcos(2x) 
If you take the second derivative of the equation above for  yp , and then substitute that result,  y′′p , along with equation for  yp  above, into the left-hand side of the original differential equation, and then simultaneously solve for the values of A and B that make the left-hand side of the differential equation equal to the forcing function on the right-hand side,  sin(2x) , you will find:
A=0 
B=−14 
Therefore,
yp=−14xcos(2x)
For more information about differential equation, visit
brainly.com/question/18760518
 
        
             
        
        
        
Answer: Ksh 6144
Step-by-step explanation:
On Thursday, a fruit vendor bought 1948 oranges on a Thursday and sold 750. The number of oranges left will be: = 1948 - 750 = 1198
On n Friday, he sold 240 more oranges than on Thursday. This means the number of oranges sold is: = 240 + 750 = 990.
The number for f oranges left will then be: = 1198 - 990 = 208
On Saturday, he bought 560 more
oranges, the total oranges that the vendor has now will be:
= 208 + 560 = 768
Since sold all the oranges he had at a price of Ksh. 8 each, the amount if money made will be:
= Ksh 8 × 768
= Ksh 6144
The vendor made Ksh 6144
 
        
             
        
        
        
-x-29=13+2x
-29=13+3x
-42=3x
x=-14