18 birds are left then regroup a ten 28 I hope it’ helps
Solving for the missing term and the missing coefficient (6a − )5a = ( ) a^2 − 35a
Let the missing term be X
Let the missing coefficient be Y
Therefore, (6a – X)5a = Y(a^2) – 35a
6a x 5a – X.5a = Y.a^2 – 35a
30a^2 – X.5a = Y.a^2 – 35a
Equating co-efficients,
30a^2 = Y.a^2; X.5a = 35a
30 = Y; 5X = 35
Y = 30; X = 7
Therefore, (6a-7)5a = 30 a^2 – 35a
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Yes it is indeed nothing else can be done to this problem
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Algebra
Factor
Factor the polynomial.
(
x
+
3
)
(
x
+
5
)
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()|[]ó
789≤
456/^×>∩∪
123-+÷<π∞
,0.%=
Factor
x
2
+
8
x
+
15
+
0
Regroup terms.
x
2
+
0
+
8
x
+
15
Add
x
2
and
0
.
x
2
+
8
x
+
15
Factor
x
2
+
8
x
+
15
using the AC method.
Tap for fewer steps...
Consider the form
x
2
+
b
x
+
c
. Find a pair of integers whose product is
c
and whose sum is
b
. In this case, whose product is
15
and whose sum is
8
.
3
,
5
Write the factored form using these integers.
(
x
+
3
)
(
x
+
5
)
