Exponential model is y=Ae^(kt)
Assume initial start is 2005, time = 0, so y = 18000e^(kt)
45000 = 18000*e^(k5)
solve for k, approx 0.1832
y = 18000*e^(1.832) = 112,435, approximately
A.) (-2,-4)
(7+3)/2=5, (10+2)/2=6
(-7+5,-10+6)
(-2,-4)
b.)r^2=244
10^2+12^2=244
r=2(61)^(1/2)
c.)(x+2)^2+(y+4)^2=244
110x0.7= 77
110-77= 33
so 33 is your answer
Answer:
3/2
Step-by-step explanation:
● (-3/8) ÷(-1/4)
Flip the second fraction by putting 1 instead 4 and vice versa.
● (-3/8)* (-4/1)
-4 over 1 is -4 since dividing by 1 gives the same number.
● (-3/8)*(-4)
Eliminate the - signs in both fractions since multiplying two negative numbers by each other gives a positive number.
●( 3/8)*4
● (3*4/8)
8 is 2 times 4
● (3*4)/(4*2)
Simplify by eliminating 4 in the fraction.
● 3/2
The result is 3/2
Answer:A B C D
Step-by-step explanation:
it is A B C D
