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Stella [2.4K]
3 years ago
12

Where is 3/4 on a number line

Mathematics
2 answers:
nirvana33 [79]3 years ago
7 0
-1 — 0 — 3/4 or 0.75 — 1
LenKa [72]3 years ago
6 0

Answer:

Step-by-step explanation:

3/4 is 0.75 and hence, is in between 0 and 1. (Note: not quite in the middle tho, but more towards the 1)

Hope this helps!

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7x-4y=3y-14 What is the literal equation for y.
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Answer:

Step-by-step explanation:

7x - 4y = 3y - 14

7x - 7y = -14

-7y = -7x - 14

y = x + 2

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On tuesday katy ran a mile in 8.34 minutes. she ran another mile in 7.89 minutes on wendsday. what was the total time for both m
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(a) By what least number must 27 be divided to make it perfect square​
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3

Step-by-step explanation:

When you divide 27 by 3 it will give you 9 and the square root of 9 gives you a perfect answer indicating that 3 is the least number that must be divided into 27

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15. Describe and correct the error in finding the intercepts of the graph of the equation.
IceJOKER [234]

Answer:

Wrong order!

Step-by-step explanation:

There's a reason why coordinates are called an "ordered pair", and for every point (a, b) a is the x coordinate and b is the y coordinate. The calculations are correct, the way reporting them are not: the point should be (3.0) and (0,2) - in fact, all points on the x axis are of the form (p, 0) and all points on the y axis of the form (0,q)

4 0
3 years ago
Use truth tables to show that the following statements are logically equivalent. ∼ P ⇔ Q = (P ⇒∼ Q)∧(∼ Q ⇒ P)
Alina [70]

Answer:  The given logical equivalence is proved below.

Step-by-step explanation:  We are given to use truth tables to show the following logical equivalence :

∼ P ⇔ Q ≡ (P ⇒∼ Q)∧(∼ Q ⇒ P)

We know that

two compound propositions are said to be logically equivalent if they have same corresponding truth values in the truth table.

The truth table is as follows :

P     Q     ∼ P     ∼Q   ∼ P⇔ Q    P ⇒∼ Q    ∼ Q ⇒ P     (P ⇒∼ Q)∧(∼ Q ⇒ P)

T     T         F        F             F            F                   T                       F

T     F         F        T             T             T                   T                       T

F     T         T        F             T            T                   T                       T

F     F         T        T             F            T                   F                       F

Since the corresponding truth vales for ∼ P ⇔ Q and (P ⇒∼ Q)∧(∼ Q ⇒ P) are same, so the given propositions are logically equivalent.

Thus, ∼ P ⇔ Q ≡ (P ⇒∼ Q)∧(∼ Q ⇒ P).

8 0
3 years ago
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