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Andreyy89
3 years ago
9

Let f(x)= x^2+1. Find and simplify the following: (a) f(x-4)= (b) f(x-4)-f(-4)

Mathematics
1 answer:
Advocard [28]3 years ago
8 0

Answer:

f(x-4) = x²-8x + 17

f(x-4)-f(-4) = x²-8x

Step-by-step explanation:

Given the function:

f(x) = x^2+1

f(x-4) = (x-4)^2+1

f(x-4 ) = x² - 8x + 16 + 1

f(x-4) = x²-8x + 17

For f(x-4)-f(-4)

f(-4) = (-4)²+1

f(-4) = 16+1

f(-4) = 17

f(x-4)-f(-4) = x²-8x + 17 - 17

f(x-4)-f(-4) = x²-8x

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What is the quotient of a number and 6 decreased by 10 = 2?
victus00 [196]
Answer:

<span>−84</span>

Explanation:

Let x be the unknown number.

From the queston we can form the equation

<span><span>x<span>(−7)</span></span>−2=10</span>

Move <span>−2</span> to the right hand side

<span><span><span>x<span>(−7)</span></span>=10+2</span><span><span>x<span>(−7)</span></span>=12</span></span>

Multiply both sides by <span>−7</span> to get the unkonwn no.

<span><span><span>−7</span>⋅<span>x<span>(−7)</span></span>=12⋅<span>(−7)</span></span><span>x=−84</span></span>



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5 0
3 years ago
V=1/3pie r^2 hail was for r I’ll give you 30 points
Gnesinka [82]

Answer:

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Step-by-step explanation:

in order to make r the subject of formulae from

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multiply through by 3

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divide both sides by π

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4 years ago
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Answer:

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7 0
3 years ago
Read 2 more answers
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