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Lana71 [14]
3 years ago
10

Cell theory has three parts: The cell is the basic unit of life in all living things, all cells come from existing cells, and __

____________.
A.
nonliving things are composed of cells
B.
the cell was discovered by Robert Hooke
C.
all organisms are made of one or more cells
D.
all cells are microscopic in size
---
this is not math lol it's science
---
don't answer if ur not sure pls
Mathematics
1 answer:
alina1380 [7]3 years ago
3 0

Answer:

C.

Step-by-step explanation:

All living things are made of one or more cells.

Can I get brainliest pls?

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Solve the following equation. Remember to check for extraneous solutions 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).
xxMikexx [17]

Answer:

-1, 2, 6

Step-by-step explanation:

We have to solve the equation as follows: 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).

Now, we have, \frac{1}{x-6} +\frac{x}{x-2} = \frac{4}{x^{2}-8x+12 }

⇒\frac{(x-2)+x(x-6)}{(x-2)(x-6)} = \frac{4}{x^{2}-8x+12 }

⇒\frac{x-2+x^{2}-6x }{(x-2)(x-6)} =\frac{4}{(x-2)(x-6)}

⇒\frac{(x-2)(x-6)}{x^{2}-5x-2 }=\frac{(x-2)(x-6)}{4}

⇒(x-2)(x-6)[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0

⇒ (x-2)(x-6) =0 or, [\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0

If, (x-2)(x-6) =0, then x=2 or x=6

If, [\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0, then x^{2} -5x-2=4

and (x-6)(x+1) =0

Therefore, x=6 or -1

So the solutions for x are -1, 2 6. (Answer)

4 0
3 years ago
Solve the quadratic equation (2x+5)(2x-5)
mote1985 [20]
If you want to multiply (2*x + 5) and (2*x - 5), you can do this using the following steps:

(2*x + 5) * (2*x - 5) = 4*x^2 - 10*x + 10*x - 25 = 4*x^2 - 25

The correct result is 4*x^2 - 25.
4 0
3 years ago
The Perimeter of the park is 318 m. Determine the length of the park<br><br> PLEASE HELP!!!!!!!!!
Vadim26 [7]

Answer:

79.5m

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
In each of the following pairs of numbers, how much larger is the first number than the second?
lapo4ka [179]

Answer: a. 154 is larger than 27 by 127.

b. 25 is larger than 12 by 13.

c.135 is larger than 127 by 8.

d.46 is larger than 24 by 22.


Step-by-step explanation:

Subtract second number from the first number.

a. 154 and 27

Difference=154-27=127

Hence, 154 is larger than 27 by 127.

b. 25 and 12

Difference=25-12=13

Hence, 25 is larger than 12 by 13.

c. 135 and 127

Difference=135-127=8

Hence, 135 is larger than 127 by 8.

d. 46 and 24

Difference=46-24=22

Hence, 46 is larger than 24 by 22.

4 0
3 years ago
Read 2 more answers
Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that p = \frac{231}{361} = 0.6399

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

E = -31*0.4095 + 21*0.5905 = -0.29

The expected value of the proposition is of -0.29.

3 0
2 years ago
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