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Lana71 [14]
3 years ago
10

Cell theory has three parts: The cell is the basic unit of life in all living things, all cells come from existing cells, and __

____________.
A.
nonliving things are composed of cells
B.
the cell was discovered by Robert Hooke
C.
all organisms are made of one or more cells
D.
all cells are microscopic in size
---
this is not math lol it's science
---
don't answer if ur not sure pls
Mathematics
1 answer:
alina1380 [7]3 years ago
3 0

Answer:

C.

Step-by-step explanation:

All living things are made of one or more cells.

Can I get brainliest pls?

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(-1)^2 × (-1)^3 × (-1)^5​
____ [38]

Answer:

1

Step-by-step explanation:

(-1)^2 = 1

(-1)^3 = -1

(-1)^5 = -1

(1) (-1) (-1) = 1

3 0
3 years ago
Solve for k. <br><br><br> 9(3-2x)=2(10-8x)
GrogVix [38]

Answer:

Step-by-step explanation:

9(3−2x)=2(10−8x)

Step 1: Simplify both sides of the equation.

9(3−2x)=2(10−8x)

(9)(3)+(9)(−2x)=(2)(10)+(2)(−8x)(Distribute)

27+−18x=20+−16x

−18x+27=−16x+20

Step 2: Add 16x to both sides.

−18x+27+16x=−16x+20+16x

−2x+27=20

Step 3: Subtract 27 from both sides.

−2x+27−27=20−27

−2x=−7

Step 4: Divide both sides by -2.

−2x −2  =  −7 /−2  

x= 7/ 2

Answer:

x= 7/ 2

3 0
3 years ago
Whole numbers are _____ integers. always sometimes never
Yuliya22 [10]
The answer is always




8 0
3 years ago
Read 2 more answers
1,000.00 at 4.5% interest for 2 years
siniylev [52]
Each year we add 4.5% interest.
4.5% as a decimal is 0.045.
We multiply by 1.045 to add this interest.
(not 0.045, this would just be the interest and wouldn't keep the whole)

To start: $1,000
Multiply by 1.045 for the first year.
Now we have $1,045.
Multiply by 1.045 again for the second year.
Now we're at 1092.025.
We need to round up to the nearest cent...$1,092.03
4 0
3 years ago
Rewrite each of these statements so that negations appear only within predicates (that is, so that no negation is outside a quan
Ghella [55]

Answer:

Follows are the solution to the given point:

Step-by-step explanation:

In point a:

¬∃y∃xP (x, y)  

∀x∀y(>P(x,y))  

In point b:

¬∀x∃yP (x, y)

 ∃x∀y  ¬P(x,y)

In point c:

¬∃y(Q(y) ∧ ∀x¬R(x, y)) \equiv  ∀y(> Q(y) V ∀ ¬ (¬R(x,y)))

∀y(¬Q(Y)) V ∃xR(x,y) )

In point d:

¬∃y(∃xR(x, y) ∨ ∀xS(x, y))  

∀y(∀x>R(x,y)) \wedge ∃x>s(x,y))

In point e:

¬∃y(∀x∃zT (x, y, z) ∨ ∃x∀zU (x, y, z))

∀y(∃x ∀z)>T(x,y,z) \wedge ∀x ∃z> V (x,y,z))  

8 0
3 years ago
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