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Elenna [48]
3 years ago
6

Multiplying a measure by a scale to produce a reduced or enlarged measure

Mathematics
1 answer:
svetoff [14.1K]3 years ago
5 0

Answer:

we conclude that:

  • If the scale factor > 1, the image is stretched
  • If the scale factor < 1, the image is reduced
  • If the scale factor = 1, the image and object will be congruent

Step-by-step explanation:

A dilation is a transformation which generates an image that is the same shape as the original object but in a different size.

The image can be obtained by multiplying the measure of the original object by a scale factor.

If the scale factor > 1, the image is stretched

If the scale factor < 1, the image is reduced

If the scale factor = 1, the image and object will be congruent

For example, if we multiply the measure of the coordinates of the vertex A(2, 2) of a triangle by a scale factor of 2, the image A' is stretched as the scale factor > 1.

Dilation with scale factor 2, multiply by 2.

  • (x, y) → (2x, 2y)

A(2, 2) → (2(2), 2(2)) = A'(4, 4)

So, the image point A'(4, 4) is enlarged.

Dilation with scale factor ½, multiply by ½.

  • (x, y) → (½x, ½y )

A(2, 2) → (2(1/2), 2(1/2)) = A'(1, 1)

So, the image point A'(1, 1) is reduced.

Therefore, we conclude that:

  • If the scale factor > 1, the image is stretched
  • If the scale factor < 1, the image is reduced
  • If the scale factor = 1, the image and object will be congruent

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Read 2 more answers
Brainest for best answer only 5 mins left show your work
Kamila [148]

Answer:

Step-by-step explanation:

Problem One

Perimeter is in meters not square meters. The equation is

2*(6.8+x) + 2*12.5= 47                Remove the brackets. Combine like terms  

13.6 + 2x + 25 = 47

38.6 + 2x = 47                            Subtract 38.5 from both sides

2x = 47 - 38.6  

2x = 8.4                                      Divide by 2

x = 4.2

Answer D

Problem 2

This problem is asking that you calculate the perimeter of a swimming pool.

The two semicircles on the ends make a whole circle.

The diameter of the semicircles is obtained from the difference of the two given lengths.

The rectangle has a length of 12. The length of the rectangle and the 2 semicircles is 16. The difference is 4. You could divide this by 2 to get the radius. I would just leave it as the diameter.

So the perimeter is pi*d + 2 * 12 [there are 2 lengths]

Perimeter = 4*pi + 24

Perimeter = 12.56 + 24

Perimeter = 36.56

Answer A

Problem 3

This is the circle inside the square.

The radius of the circle = 9

The diameter of the circle and the length of square's side = 2*9 = 18

The area of the square = s^2  where s = 18

The area of the square = 18^2 = 324

The area of the circle = pi * 9^2 = 3.24 * 81 = 251.34

The area of the Shaded area = 324 - 251.34 = 69.66

Answer C

Problem 4

b1 = 5

b2 = 11.5

h = 4.5

Formula

Area = (b1 + b2 ) * 4.5/2

Area =  (5 + 11.5) * 4.5 /2

Area = 16.5 * 4.5 / 2

Area = 74.25/2

Area = 37.125

Answer D

5 0
3 years ago
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