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3 years ago

Help please!

1 answer:

7 0

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Define x :
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Let x be the number of pounds needed.

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Find x pound :
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1 pound = $4
x pound = $4x

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Answer : Total cost = $4x
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Additional:

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When x = 9 :
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x pound = $4x
9 pounds = $4(9)
9 pounds = $36

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Answer: 9 pounds = $36
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**How do you factor -4x²+14x-6?

MAXImum [283]

2 goes into all the terms so;

2(-2x² + 7x - 3) now you could factor it:

2(-2x - 1)(x + 3)

5 0

3 years ago

If a1=10 and an=an-1+4 then find the value of a5

tamaranim1 [39]

Answer:

Step-by-step explanation:

Each term is the previous with 4 added to it.

a1 = 10, a2 = 14, a3 = 18, a4 = 22, a5 = 26

3 0

3 years ago

A Survey of 85 company employees shows that the mean length of the Christmas vacation was 4.5 days, with a standard deviation of

GenaCL600 [577]

Answer:

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

Step-by-step explanation:

We have the standard deviations for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 85 - 1 = 84

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 84 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 1.989.

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 1.989\frac{1.2}{\sqrt{85}} = 0.26$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.26 = 4.24 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.26 = 4.76 days

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

92% confidence interval:

Following the sample logic, the critical value is 1.772. So

$M = T\frac{s}{\sqrt{n}} = 1.772\frac{1.2}{\sqrt{85}} = 0.23$

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.23 = 4.27 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.23 = 4.73 days

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

8 0

3 years ago

In a certain isosceles right triangle, the altitude to the hypotenuse has length

Law Incorporation [45]

The angle bisector, median, and altitude are all the same things in an isosceles triangle.

That means that the legs of the smaller triangles created by the altitude are 4 root 2.

By special properties of an right triangle, the hypotenuse is 8.

Since the legs of the original right triangle are congruent, the area of the original triangle is 8*8/2.

Now we just simplify:

8*8/2=64/2=32

8 0

4 years ago

Four individuals pool money together to start a new business and agree to split the profits equally. N invests $6,000, X invests

shepuryov [24]

Answer:

15,000$

Step-by-step explanation:

According to the information given, profits are divided equally into 4 parts

Since the total profit for the first month is 100,000$ each party will receive a sum of 25,000$. This means that Y also receives the same amount

Now if the profits were divided in proportion to the investments made we first find the proportion on investment made by Y.

The total investment made is 6000$ + 2000$ + 8000$ + 4000$ = 20,000$. Out of this, the amount invested by Y is 8000$

finding the proportional profit of Y

$\frac{8000}{20000} (100000)$

=40,000$

So Y receives 40,000 - 25,000 = 15,000 less

4 0

3 years ago