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LuckyWell [14K]
3 years ago
10

There is an ample supply of identical blocks (as shown). Each block is constructed from four 1 × 1 × 1 unit-cubes glued whole-fa

ce to whole-face. What is the greatest number of such blocks that can be packed into a box that is 6 units tall, 7 units wide, and 8 units deep without exceeding the height of the box?

Mathematics
1 answer:
andreev551 [17]3 years ago
4 0

Answer:

336

Step-by-step explanation:

The box has an area of 336. The blocks have an area of 1. Therefore 336 blocks fit into the box.

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3 years ago
Given P(x) = 2x3 - 11x2 + 18x - 15 is divided by x – 3. Use synthetic division to find the quotient and the remainder.
katrin [286]
You can find the remainder right away by simply plugging in x=3. The polynomial remainder theorem guarantees that the value of p(3) is the remainder upon dividing p(x) by x-3, but I digress...

Synthetic division yields

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.    |           6   -15     9
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which translates to

\dfrac{2x^3-11x^2+18x-15}{x-3}=2x^2-5x+3-\dfrac6{x-3}

(and note that p(3)=2(3)^3-11(3)^2+18(3)-15=-6, as expected)
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3 years ago
What are the zeros of the quadratic function f(x) = 2x2 + 16x – 9?
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To find the zeros of this equation you need to first set it equal to zero
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2x2 +16x = 9
Now solve for x by pulling an x out of the equation
x(2x + 16) = 9
x = 9
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So your zeros would be at x = 9, and -7/2
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3 years ago
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Answer:

DEF =77.4 inches I attached an answer sheet so you can know how to work out the problem

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3 years ago
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