Answer:
C=hypotenuse [h]=50 feet
A=[base]=40foot.
B=perpendicular [p]=?
Area =?
we have
By using Pythagoras law
p²+b²=h²
B²=40²=50²
B²=50²-40²
B=√900
B=30feet
we have
Area of triangle =½×A×B=½×30×40=600feet²
<u>the roped off </u><u>area</u><u> </u><u>is</u><u> </u><u>6</u><u>0</u><u>0</u><u> </u><u>square</u><u> </u><u>feet</u><u>.</u>
<u>it</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>right</u><u> </u><u>angled</u><u> </u><u>triangle</u><u>.</u>
W=wind
p + w=158...p=158-w
p-w=112...p=112+w
SO 158-w=112+w
46=2w
23=w
SO in conclusion you have the correct answer of wind being 23km/h while the plane is going 135 km/h
HOPE THIS HELPS!
Answer:
582=-28-2287u272y7329=7373+272387##82838-78338=&*27882029··⇔㏒㏑∞°²³¥378c730+8383749=0891829.9279739383/03980339.83883383383)73837
Step-by-step explanation:
Tough call.
You may have to use Newton's Method or something like that.
Graph y=2^x and then graph n/x on the same set of axes. You may have to assign some arbitrary value to n to make this work. From the graph you can read off the approximate coordinates of the point of intersection.
