Answer:
143.26 sec
Step-by-step explanation:
Density = 4.3 g/l
Volume flow rate = 0.25 l/s
Mass flow rate = density x volume flow rate
= 4.3 x 0.25 = 1.075 g/s
This means 1.075 grams of the gas is released in 1 sec, therefore,
Time taken for leakage of 154 g of gas is
t = 154/1.075 = 143.26 sec
The answer is .5 cm. I hope it’s right
Answer: he wrote for an five hours and forty-five minutes
Step-by-step explanation:
