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3241004551 [841]
3 years ago
9

Is y=4x proportional or non-proportional

Mathematics
2 answers:
jolli1 [7]3 years ago
4 0

Answer:

No its nonportional

Step-by-step explanation:

proportional relationship doesn't have any operation between the “k” and “x” where K is the unit rate or the constant of proportionality.

Firdavs [7]3 years ago
3 0

Answer:

It is proportanal I think. But what is the value of x?

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Suppose that a company has just purchased a new computer for $1500 The company chooses to depreciate using the straight-line met
agasfer [191]

<u>Solution-</u>

The company purchased a new computer for $1500 and chooses to depreciate using the straight-line method for 5 years.

a-

As the value is depreciating, so its slope will be -ve.

Slope =- \frac{1500}{5}=-300 ( ∵ The value of 1500 will depreciate in 5 years )

y-intercept = 1500           ( ∵ At the beginning when x=0, y=1500)

Linear equation of the system,

y = mx +c ,

where,

m = slope = -300,

c = y-intercept = 1500

Putting the values,

y=-300x+1500

\Rightarrow y=1500-300x


b-

The implied domain of the function is 1≤x≤5 or [1,5]


c-

Follow the attachment attached herewith for the graph.


d-

Here,

y = the value of the computer

.

x = number of years depreciated = 3

Putting the values in the linear equation,

y = 1500-300(3) = 1500-900 = 600

∴  The book value of the computer after 3 years is $600.


e-

Here given that,

y = value of computer = 1600

x = asked = ??

Putting the values in the equation,

1600 = 1500 - 300x

⇒ 100= -300x

⇒ x= -3

∴ As the x is in negative, i.e it is impossible for the computer to be worth of 1600. It happens also because as the value is depreciating, it will always be less than 1500.



3 0
3 years ago
A^3b^2 divided by a^-1b^-3
Naya [18.7K]

Answer:

\frac{a^3 b^2}{\frac{1}{a} \frac{1}{b^3}}

And simplifying we got:

a^3 b^2 a b^3

a^3 a b^2 b^3 = a^{3+1} b^{2+3} = a^4 b^5

Step-by-step explanation:

We want to simplify the following expression:

\frac{a^3 b^2}{a^{-1} b^{-3}}

And we can rewrite this expression using this property for any number a:

a^{-1}= \frac{1}{a}

And using this property we have:

\frac{a^3 b^2}{\frac{1}{a} \frac{1}{b^3}}

And simplifying we got:

a^3 b^2 a b^3

a^3 a b^2 b^3 = a^{3+1} b^{2+3} = a^4 b^5

3 0
3 years ago
Andrew plays on a basketball team. In two games he scored 2/5 of the total number of points his team scored. His team scored 55
Harman [31]
He scored 36 points in those games.
4 0
3 years ago
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Which best describes the relationship between the lines with equations 5x +y = 4 and 20.0 + 4y = 16?
lozanna [386]

Answer:

There is no relationship, except they do intersect at the point (1, -1). Hope this helps :)

Brainliest?

7 0
3 years ago
What is 10x99<br> who is a gir
irga5000 [103]

Answer:

990

Step-by-step explanation:

 just  multiply by 10 x 99

6 0
2 years ago
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