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Advocard [28]
3 years ago
7

The cost of coffee is determined by the type of coffee beans that are mixed together. The cost of a local mix of Arabica and Rob

usta beans is modeled by the equation below, where A = the pounds of Arabica and R = pounds of Robusta: (2 points) 700A + 1200R = 1,000,000 If a mixture contains 1000 pounds of Arabica beans, how many pounds of Robusta beans should be in the mixture?
Mathematics
1 answer:
Andreyy893 years ago
7 0

Answer:

If a mixture contains 1000 pounds of Arabica beans, there should be <u>250 pounds of Robusta beans</u> in the mixture.

Step-by-step explanation:

700A+1,200R=1,000,000

700(1000) +1,200R=1,000,000 - First, plug in the A value and simplify .

700000+1,200R=1,000,000 - Then, subtract 700,000 from both sides.

1,200R=300,000 - Finally, divide by 1,200 on both sides of the equation.

R=250  - This is your value for R, or the Robusta beans.

<u>250 pounds of Robusta beans</u>

Hope this helps!

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Answer:

82.47

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area of fountain and walkway:283.53(see photo 2)

area of walkway:82.47(subtract fountain area from fountain and walkway)

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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The Graph describes the water level of creek after a rainstorm which best describes the domain in context?
belka [17]

The domain of a function are its possible input values

The domain of the function is <em>(b) all real numbers greater than or equal to 0.</em>

From the graph, we have the following observations

  • <em>t represents time (it is plotted on the x-axis)</em>
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The above observations imply that; the domain starts from 0

Hence, the domain of the function is the set of all real numbers greater than or equal to 0.

Read more about domain at:

brainly.com/question/2709928

5 0
1 year ago
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yan [13]

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x = -4, y = 8

Step-by-step explanation:

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=> y = 8

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2 years ago
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shutvik [7]

Answer:

Q = -5/8 * 2/3

Multiply both numbers like your multiplying actual numbers.

<em><u>(-5 * 2)/(8*3)</u></em>

<h2><em><u></u></em></h2><h2><em><u>A = -10/24 = -5/12</u></em></h2><h2><em><u>Hope this helps</u></em></h2>
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