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4 years ago

Use the coordinate grid to determine the coordinates of point A;

Mathematics

2 answers:

faltersainse [42]4 years ago

8 0

Answer:

Step-by-step explanation:

The coordinates of point P are (-1.4,0.6)

Step-by-step explanation:

We are given A coordinate grid shown from negative 2 to positive 2 on x-axis and negative 2 to positive 2 on y-axis. There are 4 grid lines between a whole unit of the grid.

that means each grid has a value of 0.2.

" A point labeled P is shown at the intersection of 7 grid lines to the left of the y-axis and 3 grid lines above the x-axis "

As P lies on the left of the y-axis and above the x-axis hence the x-value will be negative and y-value will be positive.

According to the given information P lies 7 grid lines to the left of y-axis.

i.e. it has x-value -7×0.2= -1.4

and 3 grid lines above the x-axis i.e. it has y-value:

y-value= 3×0.2=0.6

Hence, the coordinates of Point P are (-1.4,0.6).

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PLEASE MARK AS THE BRAINIEST

aleksandr82 [10.1K]4 years ago

7 0

Answer:

Its the first one

Step-by-step explanation:

If your an flvs student then yes its the first one and the only 2 suitable is A and C and you pick one.

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Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

vodka [1.7K]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

$\cos^2 x=1-\dfrac{225}{289}$

$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

And,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

We know that,

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Therefore, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

7 0

3 years ago

Simplify (−6.5)(−4)(−2.8)

Flura [38]

Since there are three negative numbers your product will be negative.
6.5 * 4 = 26.0
26. * 2.8 =
208
52
------------------
72.8
Answer is -72.8

8 0

3 years ago

Points b,d, and f are midpoints of the sides of triangle ACE. EC=30 and DF= 17 find AC

Margaret [11]

Answer:

Your answer should be AC=2DF=34

Step-by-step explanation:

5 0

3 years ago

Can someone help me with this?

aivan3 [116]

Step-by-step explanation:

The formula for the volume of a sphere is V = 4/3 πr³.

Given

Volume (v) = 57ft³

$v = \frac{4}{3} \pi {r}^{3}$

$57 = \frac{4}{3} \times 3.14 \times {r}^{3}$

$57 = \frac{12.56}{3} \times {r}^{3}$

$57 = 4.19 \times {r}^{3}$

${r}^{3} = \frac{57}{4.19}$

${r}^{3} = 13.6$

$r = \sqrt[3]{13.6}$

Therefore r = 2.4 ft

I gave my answers by rounding off. so if you don't round off then it's answer is 2.3 ft

7 0

3 years ago

Good afternoon mates

klemol [59]

Answer:

Afternoon has never been good tho...

Step-by-step explanation:

4 0

3 years ago