The expressions that are equivalent when m = 1 and m = 4 is;
Option B: 3m + 4 and m + 4 + 2m
We are given m = 1 and m =4;
A) 5m - 3 and 2m + 5 + m
B) 3m + 4 and m + 4 + 2m
C) 2m + 7 and 3m - 3 + m
D) 5m + 3 and 4m + 2 + 2m
For option B; 3m + 4 and m + 4 + 2m
Let's put m = 1
3(1) + 4 = 7
Also, 1 + 4 + 2(1) = 7
Similarly, let us put 4 for m to get;
3(4) + 4 = 16
Also, 4 + 4 + 2(4) = 16
In both cases, the expressions are equivalent and as such option B is the right one.
Read more about algebra simplifications at; brainly.com/question/4344214
You would multiply 2/5 by 2/2 to get 4/10, your common denominator ends up being ten so you have 3/10 and 4/10.
In the question it is given that the sum of three consecutive numbers is 162.
Let us assume the first number as = x
Then the second consecutive number is = x + 1
The third consecutive number is = x + 2
Then
x + x+ 1 + x + 2 = 162
3x + 3 = 162
3(x + 1) = 162
x + 1 = 162/3
x + 1 = 54
x = 54 -1
= 53
So the smallest of the number is 53. I hope the procedure is clear to you and in future you can easily take care of such problems without the need for any outside help.
Answer:
$1690
Step-by-step explanation:
equation: 60w+550=s
work: 60(19)+550=s
1140+550=s
1690=s
