Answer:
Step-by-step explanation:
1. First, put together the information we have. Total = 121. Emily has 40% more than Carl, and Carl has 60% more than Antony.
2. Next, set each person as a variable. Antony = x. Carl = 1.6x. Emily = 1.4 times 1.6x.
3. Next, form an equation using these variables.
x + 1.6x + (1.4 x 1.6x) = 121
x + 1.6x + 2.24x = 121
4.84x = 121
x = 25
4. Finally, plug in x to our previous variables in step #2 to find the number of stamps Emily and Carl have.
<u>Antony</u>: x = 25 stamps
<u>Carl:</u> 1.6x = 40 stamps
<u>Emily</u>: 1.4 times 1.6x = 56 stamps
By the way, is this for RSM? If so, I am working on that problem right now and I searched up the solution but couldn't find it, so I stumbled upon this. I hope this helped!
Given cost function is
c(x) =
(20 ≤ x ≤ 400)
where x is the number of thousands of square feet
total revenue will be $0.2 million dollars per thousand square feet
Revenue is 0.2 millions per thousand square feet. we know x is the number of thousand of square feet
So R(x) = 0.2x
We know Profit = Revenue - Cost
P(x) = R(x) - C(x)


combine like terms

Profit function is

Answer:
819÷13=63
Step-by-step explanation:
you divide 819 by 13 and you get 63
Let
be the weight of i-th player.
1. If the mean weight of 4 backfield members on the football team is 221 lb, then

2. If the mean weight of the 7 other players is 202 lb, then

3. From the previous statements you have that

Add these two equalities and then divide by 11:

Answer: the mean weight of the 11-person team is 
0 19 50 24 that’s as far as I could get