How many equal line segments are needed to make a line of 30 triangles

A seamstress needs to cut 15-inch pieces of ribbon from a roll of ribbon that is 9 feet length. What is the greatest number of 1

yan [13]

STEP 1:
Divide the length of the ribbon by the size of the pieces.

12 inches= 1 foot

= 9 ft ÷ 15 inch pieces
convert ft to inches
= (12)(9) ÷ 15
= 108 ÷ 15
= 7.2 pieces from one roll

STEP 2:
multiply the number of pieces that can be cut from one roll by the number of rolls

= 7.2 pieces * 5 rolls
= 36 pieces total from 5 rolls

ANSWER: The greatest number of 15-inch pieces that can be cut from five 9-foot rolls is 36.

Hope this helps! :)

4 0

3 years ago

In this problem we will be dealing with the probability density function (pdf) associated with a continuous random variable, X.

konstantin123 [22]

Answer:

$b)\ 0.568$

Step-by-step explanation:

Given

$f(x) = 6x(1- x);\ 0 \le x \le 1$

Required

$P(0.3 < x < 0.7)$

From the question, we have:

$P(a < x < b) = \int\limits^b_a {f(x)} \, dx$

So, we have:

$P(0.3 < x < 0.7) = \int\limits^{0.7}_{0.3} {6x(1 - x)} \, dx$

Open bracket

$P(0.3 < x < 0.7) = \int\limits^{0.7}_{0.3} {6x - 6x^2} \, dx$

Integrate

$P(0.3 < x < 0.7) = \frac{6x^2}{2} - \frac{6x^3}{3}}|\limits^{0.7}_{0.3}$

$P(0.3 < x < 0.7) = 3x^2 - 2x^3|\limits^{0.7}_{0.3}$

Substitute 0.7 and 0.3 for x

$P(0.3 < x < 0.7) = (3*0.7^2 - 2*0.7^3) - (3*0.3^2 - 2*0.3^3)$

Using a calculator, we have:

$P(0.3 < x < 0.7) = (0.784) - (0.216)$

Remove brackets

$P(0.3 < x < 0.7) = 0.784 - 0.216$

$P(0.3 < x < 0.7) = 0.568$

3 0

2 years ago

What are the coordinates of the endpoints of the midsegment for △JKL that is parallel to KL¯¯¯¯¯? Enter your answers in the boxe

labwork [276]

Answer:

J(-2, -1), K(4, -5), L(0, -5)

The midpoint of segment JL is

(-2 + 0)/2, (-1 + (-5))/2) = (-2/2, -6/2) = (-1, -3)

The midpoint is

(-2 + 4)/2, (-1 + (-5))/2) = (2/2, -6/2) = (1, -3)

A: (-1, -3), (1, -3)

Step-by-step explanation:

5 0

3 years ago

Electrical Resistance The electrical resistance R of a wire varies inversely with the square of its diameter d. If a 25-foot wir

kati45 [8]

Answer:

The answer is below

Step-by-step explanation:

The electrical resistance R of a wire varies inversely with the square of its diameter d:

R ∝ 1 / d

Let k represent the constant of proportionality, hence we can represent the statement as an equation:

$R=\frac{k}{d^2}\\ \\when\ R=0.5 \Omega,d=2\ mm\\\\0.5=\frac{k}{2^2} \\\\k=2\\\\The\ equation\ becomes :\\\\R=\frac{2}{d^2}\\ \\When\ d=3, we\ find\ R\\\\R=\frac{2}{3^2} \\\\R=0.22\ \Omega$

8 0

3 years ago

Can some one solve these?!

ivolga24 [154]

All you need to solve these is a knowledge of the 3 main trigonometrical ratios.
I a right angled triangle where A is a non right angle:-

sin A = opposite / hypotenuse (hypotenuse is the sloping side)

cos A = adjacent / hyptenuse ( the adjacent side is the one the angle 'sits' on)

tan A = opposite / adjacent ( the opposite side is the one opposite the angle)

So to find the length of segment x in the first problem use

sin 61 = x / 50
then
x = 50*sin61 = 43.73

and to find the length of y:-

cos 61 = y / 50
y = 60 cos 61 = 24.24

The other questions can be solved in a similar way.

7 0

3 years ago