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Dahasolnce [82]
2 years ago
6

Chang knows one side of a triangle is 13 cm. Which set of two sides is possible for the lengths of the other two sides of this t

riangle?
8 cm and 9 cm
5 cm and 8 cm 8
cm and 2 cm 2
Ô cm and 7 cm
Mathematics
2 answers:
Anna [14]2 years ago
6 0

Step-by-step explanation:

8cm nd 9cm................

natima [27]2 years ago
4 0

Answer:

8cm and 2cm

I would appreciate if my answer is chosen as a brainliest answer

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Yes, she can fit 33.75 pieces in each box

Step-by-step explanation:

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3 years ago
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Vesna [10]

Answer:

y=3x

Step-by-step explanation:

I took the test

8 0
3 years ago
A triangle has sides xcm, (x + 4) cm and 11cm, where x is a whole number of cm. if the perimeter of the triangle is less than 32
NARA [144]

9514 1404 393

Answer:

  {4, 5, 6, 7, 8}

Step-by-step explanation:

The inequality related to the perimeter is ...

  x +(x +4) +11 < 32

  2x < 17 . . . . . . . . . . . . subtract 15

  x < 8.5

The inequality related to the triangle inequality is ...

  (x) +(x +4) > 11

  2x > 7

  x > 3.5

Then possible whole-number values of x are ...

  {4, 5, 6, 7, 8}

6 0
3 years ago
Read 2 more answers
Please help!! Very urgent..thank you!!
erastova [34]

Answer : 4 times

Here it's given that ,

  • The height and base of the butterfly sitting on the stem (red butterfly) is two times greater than the height and base of the butterfly sitting on the flower .

And we need to find out how many times the area of red winged butterfly is greater than that of sitting on the flower (blue butterfly) .

Let us take ,

  • base of blue butterfly be b
  • height of blue butterfly be h
  • Area be A .

Then ,

  • base of red butterfly will be 2b .
  • height of red butterfly will be 2h .
  • Area be A' .

We know that ,

→ area of the triangle = 1/2 × base × height

So that ,

→ A/A' = (1/2 * b * h) ÷ (1/2 *2b *2h)

→ A/A' = bh/4bh

→ A/A' = 1/4

→ A' = 4A

<u>Henceforth</u><u> the</u><u> area</u><u> of</u><u> </u><u>blue</u><u> butterfly</u><u> is</u><u> </u><u>4</u><u> </u><u>times </u><u>greater</u><u> than</u><u> </u><u>that</u><u> of</u><u> </u><u>red </u><u>winged</u><u> butterfly</u><u> </u><u>.</u>

I hope this helps.

6 0
2 years ago
The mathematics department of a college has 15 male professors, 9 female professors, 6 male teaching assistants, and 12 female t
Vesnalui [34]

Given:

The number of male professors = 15.

The number of female professors = 9.

The number of male teaching assistants = 6.

The number of female teaching assistants = 12.

A person is selected randomly from the group.

Required:

We need to find the probability that the selected person is a professor or a male.

Explanation:

The total number of people in the group = 15+9+6+12 = 42

n(S) =The total number of people in the group

n(S)=42

Let A be the event that the selected person is a professor or a male.

The number of people who are professors or male = 15+9+6 = 30

n(A)= The number of people who are professors or male.

n(A)=30

Let P(A) be the probability that the selected person is a professor or a male.

P(A)=\frac{n(A)}{n(S)}P(A)=\frac{30}{42}P(A)=\frac{15}{21}=\frac{5}{7}

Final answer:

The probability that the selected person is a professor or a male is 5/7.

7 0
2 years ago
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